• WARNING: Tube/Valve amplifiers use potentially LETHAL HIGH VOLTAGES.
    Building, troubleshooting and testing of these amplifiers should only be
    performed by someone who is thoroughly familiar with
    the safety precautions around high voltages.

Vacuum Tube SPICE Models

LS50 curves from post 617 :)
Curves by Matejs model (from -5 to -25 V) looks good.
 

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Joined 2011
E180F SPICE Model

Yes i alreddy a'm using that one
now for somthing else i tried to find the model voor the E180F ( 6J9P ) if it is posted on what page can i find it

Here you go:

Code:
*
* Generic pentode model: E180F_AN
* Copyright 2003--2008 by Ayumi Nakabayashi, All rights reserved.
* Version 3.10, Generated on Fri Dec 05 13:13:13 2014
*                Plate
*                | Screen Grid
*                | |  Control Grid
*                | |  |  Cathode
*                | |  |  |
.SUBCKT E180F_AN A G2 G1 K
BGG   GG   0 V=V(G1,K)+-0.47741291
BM1   M1   0 V=(0.011310585*(URAMP(V(G2,K))+1e-10))**-1.1037743
BM2   M2   0 V=(0.57608681*(URAMP(V(GG)+URAMP(V(G2,K))/37.479334)))**2.6037743
BP    P    0 V=0.021640679*(URAMP(V(GG)+URAMP(V(G2,K))/65.058484))**1.5
BIK   IK   0 V=U(V(GG))*V(P)+(1-U(V(GG)))*0.015425385*V(M1)*V(M2)
BIG   IG   0 V=0.010820339*URAMP(V(G1,K))**1.5*(URAMP(V(G1,K))/(URAMP(V(A,K))+URAMP(V(G1,K)))*1.2+0.4)
BIK2  IK2  0 V=V(IK,IG)*(1-0.4*(EXP(-URAMP(V(A,K))/URAMP(V(G2,K))*15)-EXP(-15)))
BIG2T IG2T 0 V=V(IK2)*(0.79503106*(1-URAMP(V(A,K))/(URAMP(V(A,K))+10))**1.5+0.20496894)
BIK3  IK3  0 V=V(IK2)*(URAMP(V(A,K))+2280)/(URAMP(V(G2,K))+2280)
BIK4  IK4  0 V=V(IK3)-URAMP(V(IK3)-(0.011321203*(URAMP(V(A,K))+URAMP(URAMP(V(G2,K))-URAMP(V(A,K))))**1.5))
BIP   IP   0 V=URAMP(V(IK4,IG2T)-URAMP(V(IK4,IG2T)-(0.011321203*URAMP(V(A,K))**1.5)))
BIAK  A    K I=V(IP)+1e-10*V(A,K)
BIG2  G2   K I=URAMP(V(IK4,IP))
BIGK  G1   K I=V(IG)
* CAPS
CGA   G1  A  0.03p
CGK   G1  K  0.1p
C12   G1  G2 0p
CAK   A   K  0.1p
.ENDS
 
Yes i alreddy a'm using that one
now for somthing else i tried to find the model voor the E180F ( 6J9P ) if it is posted on what page can i find it

I have this one:

.SUBCKT E180F 1 4 2 3
+ PARAMS: MU= 56.00 EX= 1.350 KG1= 250.0 KP=6709.19 KC= 850
+ KVB= 7.9 VCT= 0.00 RGI=2k
+ CCG=8.5P CPG1=0.03P CCP=3P
RE1 7 0 1G
RE2 8 3 1G
E1 7 0 VALUE= ; E1 BREAKS UP LONG EQUATION FOR G1.
+{V(4,3)/KP*LOG(1+EXP((1/MU+V(2,3)/V(4,3))*KP))}
G1 1 3 VALUE={(PWR(V(7),EX)+PWRS(V(7),EX))/KG1*ATAN(V(1,3)/KVB)}
G2 8 3 VALUE={(PWR(V(7),EX)+PWRS(V(7),EX))/KC*(2.5708-ATAN(V(1,3)/KVB))}
E2 8 4 VALUE={0}
RCP 1 3 1G ; FOR CONVERGENCE
C1 2 3 {CCG} ; CATHODE-GRID 1
C2 1 2 {CPG1} ; GRID 1-PLATE
C3 1 3 {CCP} ; CATHODE-PLATE
R1 2 5 {RGI} ; FOR GRID CURRENT
D3 5 3 DX ; FOR GRID CURRENT
.MODEL DX D(IS=1N RS=1 CJO=10PF TT=1N)
.ENDS

Please check which one is better.
 
When available, the L's are based on the data provided by the manufacturers, else, they are based on the measurements e.g., as shown by Yves M. and others.

Some manufacturers provide the primary inductance (obviously) based on on the "old" test procedure (5 Vrms/50Hz), some, like Edcor does not provide this info at all and some. like Amplimo gives the "maximum" value, whic refers to some 200 Vrms tets voltage.
The primary inductance value can vary from, say 25 H to 125 H depending on the test voltage.

As an example, I measured the Lp of Indel TGL40/001, which is a OPT I have used a lot.

The results with different test voltage (50 Hz):

1Vrms......6.8 H
5 -"- .......9.4 H
50 -"-..... 23 H
100 -"- ....32 H
200 Vrms...43 H

When simulating, the results with 6.8 H and 43 H are very, very different.
So, this is not that simple matter.