Wingston Churchill said:A puzzle wrapped in a triangle inside a square ...
I am hoping that Cal sets us a hard one next. I have solved the Riemann Hypothesis, an unexpected solution, but this page is too small to contain it.
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Are you about to fight a duel?I am hoping that Cal sets us a hard one next. I have solved the Riemann Hypothesis, an unexpected solution, but this page is too small to contain it.
Quanta Magazine
ROFLI have solved the Riemann Hypothesis....
Prophetic Words from soundbrigade...
Looks hard.
Winston Churchill said:A puzzle wrapped in a triangle inside a square ...
Looks hard.
I wish people wouldn't post unnecessarily large images.
I apologize for this. When mountain hiking i should solve puzzles without posting images from my mobile
He likes the apparent simplicity of this one.
I think it might be (324/49)*pi. I will check when at home!
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The proof is missing at this link, it just gives a cook book result.
This is for cheaters who do not want to understand a thing.
Thanks to internet we are well on the way to Idiocracy. Idiocracy, the movie.
If you calculate the sides of the four triangles, it will be easy. Pythagoras' theorem a^2 + b^2 = c^2, here c = 10 and a x b = 24, then a = 6 and b = 8. Proof: 36 + 64 = 100, and (6 x 8) / 2 = 24. You can use some math to get to this result.
Now we calculate the radius of the circle. Draw three radii with length r, two of them is perpendicular to the sides of the triangle, one is perpendicular to the hypotenuse (that is the side of the inner rectangle). (a - r) + (b -r) = 10 the length of the hypotenuse. From this equation r = 2. The area is r^2 x Pi = 4 x Pi.
Now we calculate the radius of the circle. Draw three radii with length r, two of them is perpendicular to the sides of the triangle, one is perpendicular to the hypotenuse (that is the side of the inner rectangle). (a - r) + (b -r) = 10 the length of the hypotenuse. From this equation r = 2. The area is r^2 x Pi = 4 x Pi.
The proof requires more jiggery-pokery than mathematics!
There are a large number of proofs of this proposition online; the one below is among the simplest
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