ZV7-T (transformer)

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I believe

R4 is a very high compared with R2
Therefore, feedback amount via R4 is consided very small
Approximately, R4 and R6 is just a dc voltage divider.

Actually, the voltage gain must be decided by the relation
between the loop gain and the fraction of R3 and P1 . . .

If R2 is increased, it would be another story
Then, the voltage gain could be predicted as R4/R2.
R6?
In this case, R6 takes a role for the frequency bandwidth decision of the closed loop

Happy New Year
 
Babowana said:
I believe

R4 is a very high compared with R2
Therefore, feedback amount via R4 is consided very small
Approximately, R4 and R6 is just a dc voltage divider.

Actually, the voltage gain must be decided by the relation
between the loop gain and the fraction of R3 and P1 . . .

If R2 is increased, it would be another story
Then, the voltage gain could be predicted as R4/R2.
R6?
In this case, R6 takes a role for the frequency bandwidth decision of the closed loop

Happy New Year


babo........please confirm my mails
 
Babo, Isn't there a current relationship here? Where, considering no current into the gate, and excluding R6, you would have the same current through R2 and R4 with 0 Volts at the gate node(0 voltage/current summing point?). Where all your input voltage across R2 would dictate the current. And that current across the R4 would dictate the amount of feedback/gain???
However, we have an R6??? With an AC effect also. So, some of the current from the output, is lost to ground. And, actually, some of the input voltage and current flows to GND through R6 also???
I beleive the PLH had a similar circumstance???
I'm not sure of the AC implications of R3 and RP1 in john's current circuit. And, I thought them, in the interest of ZEN philosophy, uneeded... For everyone's info, my simulation of the Circuit in post #271, using no R3 or RP1 and a 20K R2 says: Using a 2V p-p input, I see 1.35V p-p at the gate node(in phase with the input signal), and 18.56V p-p at the output(Naturally 180 degree's out of phase)... That is a gain of 9.28??? Obviously the R6 is messing up anyone's typical idea of what the gain is in my circuit... And John's also... It is not just the contribution of the R3 and RP1? But, what is it?
Ohh, I forgot, My sim is not exactly like #271,,, I used 8 ohm loads and a 40V supply 😀
:smash: :smash: :smash:
:xmastree: :cheers: :wave:
 
Let’s have a look only with R2, R6 and R4.
And assume the buffer gate as a virtual ground.

We thevenize R2 and R6 with Vin.
Then Rth=R2//R6, Vth=Vin x R6/(R2+R6)
So, Vout=Vin x R6/(R2+R6) x R4/ (R2//R6)
Conclusion: Vout/Vin=R4/R2, leaving R6 canceled off.
(Refer to Malvino’s Section 40-something, linear op-amp,
I don't remember the section number well . . .)

Whatever R6 value is, the gain is expressed as R4/R2.
I.e. prediction of the gain is 442K/221= 2000 ???
This is not feasible, IMHO :smash:
The measurement will show much lower than this.

The gain must be earned by the combination of
the open loop gain and R3&P1 feedback

🙂
 
I'm already lost in references in last few pages of thread........but-if your talk is about circ in post #271,then only OL is worth considering;
I can't see any feedback path anywhere........at least not effective and contributive ;
if we presume that gate resistors are 20K ,and feedback resistor is 442K........through 442K we have positive feedback?


I'm gonna sleep.......I'm already stoooooooooopid enoughjkl;'

edit
stoooopid input buffer is non inverting
there is just stooopid ZM with even more than usual 4 eyes.

stooopid amp

sez lil' foxie, turnin' own back from grape tree 😉

edit edit

I found carp's scmtc 158 pages back.......increase input resistor or-even better put 221 to gate and put in his place something as 10K..................decrease 442 K to 47K and then see what ya get.........susy,mebbe with few aditional problems ,maybe not.......sorry-I can't cover so much threads ,I'm not Papa 😉

in any way
 
Babowana said:




My reference is post#227 on page(23).

BTW I got your 21 mails, each of wich includes 2MB size attachment, total more than 40MB . . . But, I could not open the attachments. I will re-try to open them tonight.

🙂


just sent you explanation mail ( I killed ya with 40 megs,and then I giv ya expl 😉 )........

if this is (attached) circ ,then all my "edit" mumbo jumbo few post above is regarding that......
 

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This is the current configuration:

Btw, there must be some feedback. When I inserted a signal at the gates of the power fets, there was a slight blip on the lower tip of the output sine wave. When the signal was placed in it's normal position (before the buffer), the blip disappeared at the output.🙂
 

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John, What are you using for V+? Do you still have something like 23V at the speaker outputs? And, are you running a S.E. input to the +Input and grounding the -Input?
I think those 36 ohm R's to ground are mighty hot??? You could probably get away with something a little higher in value???
I still have't figured out the gain thing totally. Other than to say, R3 and RP1 are not effecting gain. And when I set up my circuit of post #271 without any feedback, I get an open loop gain of 20 😀 That's with a S.E. input, with the - Input GNDed and differential output.
:xmastree: :xmastree: :xmastree:
 
Okay . . .

Reference: post#294
Reference: post#285

Attached just for fun

See you in 2007, all babos!
I'm leaving for my wife
I could be an energyman this time
I got something powergenerating, he he . . .

Happy New Year !!!!!!

🙂
 

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Hi flg,

I'm now running 29 volts at the input and 25 volts out of the choke.

The 36 ohm resistors are what I have on hand at the moment. When I get back to work, I'll purchase resistors closer to 50 ohms. The 36 ohm resistors are sandwiched/clamped into my heatsink ribs and spacers--beautiful set-up. If 72 ohms were acceptable, I could always series the 36 ohm resistors. I have a whole sack full.🙂 There's plenty of room in the heatsink.

The single-ended output from the receiver is channeled through a device that supposedly adapts it to xlr/balanced mode. I don't know what it's doing internally, but I do know that its negative output is flat-lined on the o'scope. So I assume the ZV7-T amp is now single-ended.

I did connect everything to a true balanced Aphex single-ended/balanced converter and didn't care for the results. The ZV7 is accurate sounding, but lacks that wonderful warmth that I've grown so accustomed to. I'm staying with the single ended approach.

As configured, this amp exhibits excellent micro-detail. Its midrange isn't quite as full as I'd like, but the details are fascinating. It's like the amp focuses on them at partial exclusion of the music's body--perhaps it overpowers the body. I'm not saying that this is the perfect solution, but it certainly is enjoyable. And, since I'm hard of hearing in the upper frequency range, I find this to be quite a blessing.🙂

babowana, I'll try to sort out what you're trying to teach me--thanks for the drawings.

I really have had a good time with you guys, and feel tremendous appreciation for your involvement.

Many thanks,

John
 
We should use the inverting configuration because the amp as a whole is inverting. Your feedback from the + input side is negative after the Power FET.
The trouble is, unlike the opamp configurations, that there is a DC voltage at the output that will appear at the Buffer gate through the feedback network. We need to keep that DC gate voltage at something useable. The R6 resistor can do that but it has an effect on the AC signal also. That messes with our simple understanding of the feedback network.
In the circuit I suggested, Post #271, I set up the Buffer gate voltage properly to also bias the Power FET and disposed of the C2, R1 and RP1 components. I can easily see what the gain is when working on the simulator.
 
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