Subminiature tube/valve guitar amplifier

I'm using the Hammond 1750E for 2 - 6P30B's in push-pull @ 300V. I figured out I'm going to have to put a 16 ohm speaker on the 8 ohm secondary to reflect 17,000 ohms on the primary to keep everything happy. (Apparently, 6P30B has a load resistance approx. 8500 ohms @ 300V.)


Set me back $55 so I can see why some guys like to use line voltage tranformers you can pick up for $10 or so. I just have too much time invested in this to try something that might not have good frequency response.
 
Hi,
I have a doubt on the specs of the transformer.
It is not obvious to me, the correspondence between the left and right columns.
Do the primary impedances correspond to a load of 4, 8 or 16 ohms?
Cheers
Pedro
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The ratio of transformer is: n1:n2 = 1000/4 = 2000/8 = 4000/16 = 250 -> same for the 3 "cases" of course.

It means that the output impedance (where you plug the speaker) is 4R (R is ohm) if the input impedance (tube side) is 1k, 8R if impedance on the tube side is 2k, ... For power it is the same thing:

1. P=10W @ 4R
2. P=5W @ 8R
3. P=2.5W @ 16R

For example, if your impedance on the tube side is 1500 ohms then output impedance will 6 ohms.
 
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Hi,
Thanks for the reply. My doubt it was regarding that correspondence, from the column on the left to the right. If they really wanted to say 1k to 4; 2k to 8; etc , shouldn't the others be there (32 and 64)?

I believe your calculations are not correct, since the ratio between impedances, doesn't equal the ratio of number of turns, but the square of the number of turns.

If P=V^2/R, where V=N
we can say that:

Pp=Ps -> Vp^2/Rp=Vs^2/Rs.

As Vp/Vs=Np/Ns

Np^2/Ns^2=Rp/Rs -> Np/Ns = squareRoot(Rp/Rs)= squareRoot(250)=15.8

Best regards,
Pedro
 
Hi,
I don't know if you agree with this but, to me, the list on the left only tell us correspondence between power and resistance, whereas the second the output impedances available to be used. BAsically 2 columns that tell you which inputs and outputs are available.
So, to me, it's not 1k to 4ohm, 2k to 8 ohm, etc. All of them could be used in any combination, 1k with 4ohms, 2k with 4 ohms, 1k with 8 ohms, etc.
If I am correct, I don't know for which value of secondary output, the primary resistance was calculated.

Any thoughts on this?
Cheers,
Pedro
 
You maybe right because I supposed that the ratio was constant. However, it is maybe not the case. If you have access to intermediate transformer parts (through some of wires), you can have multiple ratio and so have all possible combination. I think we should see the wiring diagram but in the picture, only 2 wires in one side and 3 wires on the other side. No wiring diagram on Hammond website.
 
Hi, there are some better datasheets out there (check mouser, every part has a datasheet). I would guess it is the same as other transformers out there. (725, 300, 400, 600, 900 turns at the primary and 48,18, 30 turns in the secondary)

The primary impedances are for all the secondary impedances. You can get 16k using 4 ohms on the 4 ohms tap, 8 ohms on the 8 ohms tap and 16 ohms on the 16 ohms tap. Because the ratio is kept constant if you use the right tap.

If you mismatch speaker impedance and tap impedance, on the other hand, you can get 64k with a 16 ohms speaker on the 4 ohms tap.
 
Hi
Can someone please help me finding the pinout for this tube?
I was expecting to see a mark of some kind, but I can't see one.
Please check the pictures attached.
Thanks,
Pedro
 

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