Power amp under development

Hi guys

have a question,.. who did build NMOS since today too and had similar experience...

Input differential Transistor T1 T5 (2SC2240 or 2SC1845) are hot

after changed R5 18K from quais schematic to 40 K temperature from T1 and T5 (2SC2240 or 2SC1845) is low

I think 18K in original design is to low

willl send latest schematic and PCB LAYOUT at weekend
 
attachment latest NMOS design

changes are R6 from 18 to 40K reduces power dissipation in differential input stage

Industrial DIY PCB are available
 

Attachments

attachment latest NMOS design

changes are R6 from 18 to 40K reduces power dissipation in differential input stage

Industrial DIY PCB are available

Hi Qsa,

Sorry but I disagree with your first stage configuration. Using a LED as the reference for T3 means that about 5.5mA will flow through R7 and R6. The voltage across R6 if it is 40k will be 220v (or at least try to be). This is more than the rail voltage meaning there is no voltage left for T3. So we do not have a proper constant current source (CCS). Even 18k is too high for 5.5mA as this will try to have 99 volts across it.

If I were you I would reduce the CCS current to 3mA by replacing R7 with a 390 ohm resistor. Then replace R6 with an 18K resistor. I would also replace R4 and R12 with 390 ohm resistors and drop the voltage across these to 0.6 volts (you currently have 1.3 volts here).

In the second stage CCS your choice of 47 ohms as R19 means that 25mA will flow through T7 and T8. This amouns to a dissipation of 4 watts and is completely unnecessary. I would change R19 and R15 to 100ohms and reduce the current through this stage to 12mA.

Cheers
Q
 
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Hi

I have some MTE215N10E

Can I use them for the Quasi Nmos 200 ?

Thanx

Paul
 

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  • MTE215N10E.gif
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350 mk2

how about replacing the 5.1v Zener with a pair (or 3) of ~1.9V LEDs?
Maybe combine R11 & R12 and use a 36K with no connection to ground.
What is the design current through R11 & R12?

What about hFE recommendations for T1, T4 & T6?
1.8/hFE T1 + 1.8/hFE T4 = 10/hFE T6.
But this requires a very high gain T6. Instead add a resistor from +ve supply rail to junction of T1+T4 bases. This makes a better job of balancing the currents coming out of the mirror.
 
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