Alpha Nirvana 39w 8ohm Class A Amp

Hello guys,
Yesterday night while stuffing my pcbs, I checked the 4R schematic via Andy's BOM. I discovered that C124 for 8R or C6 for 4R has a different value according to the schematic by Hugh. There is a 220uF cap in Andy's BOM. In the schematic, there is a 100Uf cap. I don't know whether is critical or not. Hugh and XRK can answer that question.
 
Hello X,
Would you be so kind as to clarify the question I launched in a previous post:

-Hi, I have a question about the input impedance of the 20w version of the "Alpha Nirvana".
The thing is that I don't know if the input impedance is equal to R1+R2=222,5k, or to R1+R2//R3=22,5k.

Thanks in advance-

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I really want to give this Alpha Nirvana a try.
My first DIY Amp was the Aksa 55 that I built about 18 Years ago with great assistance from Hugh.
Is there anything that can be optimized for mid/high range in an active system?

Klaus
 
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My apologies guys, I have been distracted by holidays.........
220uF for feedback shunt cap is fine, slightly better bass than 100uF but whilst you will set it in the math and the measurements it makes almost zero effect on the subjectives. Bass is already very strong with this amp, and has a rising damping factor below 1KHz.
Input impedance of the AN39 is R2//R3 and also in parallel with the Zin of the base T1. I had not realised this until now, and this means the Zin of the AN39 is dominated by the base input, not simply R2//R3 I had thought before.
The Zin of the base is:
Rin = Beta * (Vt/Itot) * 4, with Vt = kT/q , about 26 mV at room and Itot = The total emitter current of the transistors. (2.6mA here)
This gives about 100 x 26/2.6 x 4 = 4k
So when you put in 22.9k, the combination of R2 and R3 with the base impedance, you get 3k4!
This is a lot less than I'd expected, but could be hugely by adding degen resistors on the LTP transistor emitters.

Cheers,
Hugh
 
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Input impedance of the AN39 is R2//R3 and also in parallel with the Zin of the base T1. I had not realised this until now, and this means the Zin of the AN39 is dominated by the base input, not simply R2//R3 I had thought before.
The Zin of the base is:
Rin = Beta * (Vt/Itot) * 4, with Vt = kT/q , about 26 mV at room and Itot = The total emitter current of the transistors. (2.6mA here)
This gives about 100 x 26/2.6 x 4 = 4k
So when you put in 22.9k, the combination of R2 and R3 with the base impedance, you get 3k4!

That's a bit low for general use, I would've thought, Hugh?

Luckily for me, the Zout of the Topping E30 DACs I'm using (which feed my ANs) ... is only 20 ohms!

This is a lot less than I'd expected, but could be hugely (increased?) by adding degen resistors on the LTP transistor emitters.

For those who need to do this - because their preamp/DAC doesn't have a very low Zout - how are they going to fit these degen resistors onto the PCB?
 
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