excellent quasi-saturation behavior./QUOTE]
What would "excellent" mean in this case?
First, the much-used KSC3503E. At 15mA Ice, when Vce drops below 5V, Ice starts to shut off. This would be the opposite of excellent quasi-sat behavior in my opinion. I grappled with this recently with a VAS stage that was visibly distorting long before clipping.
Next, the TTC004B. At almost 20mA Ice, the Vce where the transistor starts to shut off is less than 0.5V. This would be excellent quasi sat behavior.
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lemme see ....... 28Vac will give , in ideal world .....39V6dc ........ shave volt or so for losses , counting that Iq is low enough , so no loading down the rail
so , you have 2x37Vdc on disposal
let say that, from these rails, you can squeeze 70Vpp in best case on amp output
divide that with 2 - you're getting Vp
divide Vp with 1.41 - you're getting Vrms
so , we have 24V75rms as result .... and let say that we are using 8R declared load
P=(Urms^2)/Rload = 612.5/8=76W
so , yes , you can , but without calling it "100"
so , you have 2x37Vdc on disposal
let say that, from these rails, you can squeeze 70Vpp in best case on amp output
divide that with 2 - you're getting Vp
divide Vp with 1.41 - you're getting Vrms
so , we have 24V75rms as result .... and let say that we are using 8R declared load
P=(Urms^2)/Rload = 612.5/8=76W
so , yes , you can , but without calling it "100"
lemme see ....... 28Vac will give , in ideal world .....39V6dc ........ shave volt or so for losses , counting that Iq is low enough , so no loading down the rail
so , you have 2x37Vdc on disposal
let say that, from these rails, you can squeeze 70Vpp in best case on amp output
divide that with 2 - you're getting Vp
divide Vp with 1.41 - you're getting Vrms
so , we have 24V75rms as result .... and let say that we are using 8R declared load
P=(Urms^2)/Rload = 612.5/8=76W
so , yes , you can , but without calling it "100"
Thank you very much for all the calculations.
I don't have much technical knowledge, I'm just a practitioner. 🙂
What kind of transformer is needed (how many volts and amper, center tap vs.) for 100w?
sq. root of 800 , multiply with 2 multiply with 1.41 , divide with 2 - that's the half sine
add few volts on that , that's the Vdc rail
add 1 or 2V , divide with 1.41 , that's Vac secondary , one
you need two, of course
you need at least twice VA of xformer , considering channel power , so 200VA
read this: http://www.firstwatt.com/pdf/art_power_supplies.pdf
one funny guy already chew it for ya
add few volts on that , that's the Vdc rail
add 1 or 2V , divide with 1.41 , that's Vac secondary , one
you need two, of course
you need at least twice VA of xformer , considering channel power , so 200VA
read this: http://www.firstwatt.com/pdf/art_power_supplies.pdf
one funny guy already chew it for ya
Last edited:
lemme see ....... 28Vac will give , in ideal world .....39V6dc ........ shave volt or so for losses , counting that Iq is low enough , so no loading down the rail
so , you have 2x37Vdc on disposal
let say that, from these rails, you can squeeze 70Vpp in best case on amp output
divide that with 2 - you're getting Vp
divide Vp with 1.41 - you're getting Vrms
so , we have 24V75rms as result .... and let say that we are using 8R declared load
P=(Urms^2)/Rload = 612.5/8=76W
so , yes , you can , but without calling it "100"
sq. root of 800 , multiply with 2 multiply with 1.41 , divide with 2 - that's the half sine
add few volts on that , that's the Vdc rail
add 1 or 2V , divide with 1.41 , that's Vac secondary , one
you need two, of course
you need at least twice VA of xformer , considering channel power , so 200VA
read this: http://www.firstwatt.com/pdf/art_power_supplies.pdf
one funny guy already chew it for ya
Thanks 🙂
Hi all,
today the boards arrived ... But the customs and DHL wanted to see money and that because of 0.30€ over the exemption limit .
So, 10 boards are around 50€ and now a stereo set costs 10€ + shipping to you. If someone jumps out is no problem for me (someone on waiting list). I will calculate the shipping costs at the weekend and contact you.
1. manniraj
2. Cambe
3. HerrErnie
4. yuujin
Please send me via pm your address, thanks!
today the boards arrived ... But the customs and DHL wanted to see money and that because of 0.30€ over the exemption limit .

So, 10 boards are around 50€ and now a stereo set costs 10€ + shipping to you. If someone jumps out is no problem for me (someone on waiting list). I will calculate the shipping costs at the weekend and contact you.
1. manniraj
2. Cambe
3. HerrErnie
4. yuujin
Please send me via pm your address, thanks!
Hi all,
all boards payed an no more left, the last two sets will be shipped tomorrow to USA & India.
all boards payed an no more left, the last two sets will be shipped tomorrow to USA & India.
And so the AB100 marches on.
Circuit originally designed for Nirvana Electronic Works:
Nirvana Electronic Works NEW A-60 Amplifier.WOOW | Audiogon Discussion Forum
After they went away, then used by Portal...
Portal Audio Panache integrated amplifier | Stereophile.com
Now diyAudio.
You will be amused to know that I have never made a nickel on it.

Circuit originally designed for Nirvana Electronic Works:
Nirvana Electronic Works NEW A-60 Amplifier.WOOW | Audiogon Discussion Forum
After they went away, then used by Portal...
Portal Audio Panache integrated amplifier | Stereophile.com
Now diyAudio.
You will be amused to know that I have never made a nickel on it.

A few days ago I got such a nice "donor" , each side heat-sink to-3 pre-drilled, but only for one pair.
think I could get in there smaller AB100 - let's call it AB 60 as ZM suggested 😀.
I will have to paint it white and make a new aluminum or wooden front panel.
think I could get in there smaller AB100 - let's call it AB 60 as ZM suggested 😀.
I will have to paint it white and make a new aluminum or wooden front panel.
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Interesting history. Thanks for posting it, Papa.
I'm glad that the design made it's way to diyAudio, but sorry that you never made anything on it.
I'm glad that the design made it's way to diyAudio, but sorry that you never made anything on it.
So would like to purchase some boards! Do I understand correctly that no more are available. Any other US group buy in process or planning?
So I have inquired about Gerber files for this design? I was told they exist. Not sure where. Anybody have any info on this. Thanks in advance.
@Mr. Pass,
little questions ....
where is R35 on your boards
C9=0pF - what means that?
means 2210=221R / 4751=4k75R
Thanks!
little questions ....
where is R35 on your boards
C9=0pF - what means that?
means 2210=221R / 4751=4k75R
Thanks!
Attachments
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C9=0pF is a synonym for DNI. Do Not Insert.
It means that there is a "footprint" for C9 on the PCBoard layout, but your assembly technician is told not to stuff or solder any component in that footprint. The amount of capacitance we want in this position is: zero. No capacitor at all.
One reason you might put this in your design is: for future flexibility. If, God forbid, WhizBang Semiconductor stops making the BL74JSK device, or if they accidentally let their inventory pipeline go empty*, you have a plan. You'll buy the almost-as-good M44D74GN from ErsatzPLC, and compensate for its imperfections by stuffing an 8.2pF capacitor in position C9. This reduces the amplifier bandwidth by 15% but you're still in production. Now instead of ±0.25dB from 2 Hz to 110 kHz, the modified amp is "only" ±0.25dB 2 Hz to 93 kHz. Still quite listenable.
*because your fierce competitor Panasony paid 10% more to buy up every last part in existence
_
It means that there is a "footprint" for C9 on the PCBoard layout, but your assembly technician is told not to stuff or solder any component in that footprint. The amount of capacitance we want in this position is: zero. No capacitor at all.
One reason you might put this in your design is: for future flexibility. If, God forbid, WhizBang Semiconductor stops making the BL74JSK device, or if they accidentally let their inventory pipeline go empty*, you have a plan. You'll buy the almost-as-good M44D74GN from ErsatzPLC, and compensate for its imperfections by stuffing an 8.2pF capacitor in position C9. This reduces the amplifier bandwidth by 15% but you're still in production. Now instead of ±0.25dB from 2 Hz to 110 kHz, the modified amp is "only" ±0.25dB 2 Hz to 93 kHz. Still quite listenable.
*because your fierce competitor Panasony paid 10% more to buy up every last part in existence
_
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Hello Mark (hope it ok),
thanks for your answer for C9!
Sorry, my english is not the best ... what I understand is: flexibility and if C9=8.2pF then is the bandwidth "only" ±0.25dB 2 Hz to 93 kHz.
thanks for your answer for C9!
Sorry, my english is not the best ... what I understand is: flexibility and if C9=8.2pF then is the bandwidth "only" ±0.25dB 2 Hz to 93 kHz.
There is only one person who knows exactly why Nelson Pass included C9 in his PCB layout, and that person is not me.
I offered a hypothetical scenario including fake names of semiconductor companies, nonexistent part numbers, and completely bogus bandwidth specifications, to illustrate one possible reason why someone MIGHT include C9. It was a hypothetical scenario. A work of fiction. A story from the land of make-believe.
The good news is: you don't need to know why there is a footprint for C9 on the PCB. Just be sure not to stuff and solder anything there, and live a happy life.
I offered a hypothetical scenario including fake names of semiconductor companies, nonexistent part numbers, and completely bogus bandwidth specifications, to illustrate one possible reason why someone MIGHT include C9. It was a hypothetical scenario. A work of fiction. A story from the land of make-believe.
The good news is: you don't need to know why there is a footprint for C9 on the PCB. Just be sure not to stuff and solder anything there, and live a happy life.
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