That is not correct, once that driver is part of a loudspeaker system. Faster response to an impulse would mean that the speaker runs to a higher frequency. For a bare speaker the impulse response would indeed be better, but if you put it in a loudspeaker you would remove the high frequencies with a crossover. Then the only factor differentiating the impulse responses of different drivers would be if there are resonances in the pass band. For a direct radiator, which operates between the box resonance and the cone breakup frequencies, this is already close to perfect.
(This of course neglects diffraction and resonances of the surround etc. but that is not my point.)
I Think that I am going crazy, I need to see something concrete, hope that the AE LO15 drivers will arrive soon 😡
Concrete speakers has been seen before.
Do all the preparations, while you wait.
When drivers turn up, you just have to throw them in and listen.
Do all the preparations, while you wait.
When drivers turn up, you just have to throw them in and listen.
F=MA Force equals Mass x Acceleration
If the mass is increased (of the cone) the acceleration decreases. Put simply, a lighter cone responds quicker.
I am losing the plot here slightly. I am saying that assuming the same area, that a cone that weighs 10gm will respond quicker than one that weighs 40gm.
All other things being equal it will have a different bandwidth. Is that what you are saying?
My previous post might be unclear, so let me try to rephrase it:
Let's say you are designing a two way loudspeaker. There is a target transfer function (frequency response) for the woofer, e.g. fourth order butterworth low pass at 3 kHz. Using a crossover you shape the transfer function to your target. Let's assume the target is met. For the result it does not matter how you got there. A light-coned woofer or one with a heavy cone would now both give the same transfer function: the target transfer function. As the impulse response can be derived from the transfer function*, those impulse responses would also be identical.
*It must be noted that this is only true for minimum phase systems.
Let's say you are designing a two way loudspeaker. There is a target transfer function (frequency response) for the woofer, e.g. fourth order butterworth low pass at 3 kHz. Using a crossover you shape the transfer function to your target. Let's assume the target is met. For the result it does not matter how you got there. A light-coned woofer or one with a heavy cone would now both give the same transfer function: the target transfer function. As the impulse response can be derived from the transfer function*, those impulse responses would also be identical.
*It must be noted that this is only true for minimum phase systems.
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If you increase the force applied to the heavier cone, you can equal the acceleration initially obtained with the lighter cone.
Another thing to consider : the material of the lighter cone has probably less self-damping properties and may present resonances which compromise the impulse response.
SPL is proportional to the cone acceleration. Therefore a speaker with higher acceleration is not quicker but more efficient.
Regards
Charles
Regards
Charles
More efficient if the higher acceleration is given for the same electrical power.
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