You can use those parts together.
Thank you Salas.
Finally got myself together and did some calc
🙂
Using "Id (ccs) = Idss (1 - (Vgs / Vp))2"
and "Vgs = Id x Rs"
For a K369 idss = 10.3mA and Rs = 3.9ohm I estimate Id = 8.9mA
For both Q1 + Q2 we have a total of 17.8mA Idling
I want 4volts on top of folded collector R4 (2200), so current on R4 is 1.818mA
Total current on R13 (1200) is then 19.62mA
Vdrop on R13 is 23.54V
Having 8V on the folded base we have 8,6V on the emitter of Q3 so we already have a Vdrop of 23.54 + 8.6 = 32.14V
If I set Vp = 35V than I need to drop 35-32.14 = 2.86V on R12//Vr1 for a current of 19.62mA and that gives me 146ohms.
So it seemed I needed to increase R13 or R12/vr1..... but then I remembered you suggested to use alternative Vp.... if I lower Vp to 34v, everything is in place naturally.
Now I only need to drop 1.86V on R12//Vr1 and the resulting resistance is 95ohm.
Quite flexible and brilliant engineering.