New ClassD project Starting from 0

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Luka!
Is this a serious question? Cross-section (=area) of circle is A=d^2*pi/4 = 0.08*0.08*3,14/4=0.005 mm^2 (=> total area of 1 mm^2).

Hello Pafi,

I have 40x0.08mm homemade litzwire. That means that total diameter is 40*0.08 = 3.2mm thus, 3.2*3.2*3.14/4=8.03mm^2
BUT if i calculate on only one 0.08 wire and multiply by 40:
0.08*0.08*3.14/4=0.005mm^2*40=0.20mm^2

so witch is the correct way to calculate the area of a litzwire inductor

Best regards,
 
To JEJ:

Taught so to, thank you for clarifiing.
Now the other stupid question:
What is the amount of amps that can be drawn from 0.20mm^2 in a 50KHz smps?

I am building SMPS and I don't have litzwire so I have to make it myself.

Regards,
 
...
Everything happening at source inductance appears at the gate too, but this may be actually useful because parasitic resonances may be damped indirectly to some extent with very low dissipation through the gate, and damping the rest directly on the switching node becomes much easier...

Hi Eva,
This is interesting, are you talking about something fancier than just slowing down the gate? In my mind I started seeing little tank circuits on the gate to tame big problems on the power side. But won't this cause trouble with your compensation? Maybe I took this too far🙂
 
Savu,

For a SMPS's transormer at 50KHz you must take into account the skin effect. The formula is 66/(F)^0,5 with F in Hertz
The current density is about 4 to 6A by mm^2.
For example at 50 KHz you can use a diameter of 0,3mm for your wire corresponding to 0,068mm^2 and use 14 x 0,3mm if you have a current of 6A
Note this is the rms current!
What is your topology?
 
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