Sorry if I gave any wrong information with regards to the schematic on page 37.
On my schematic the information I gave was correct. Contacting Jan is the right thing to do for clarification.
On my schematic the information I gave was correct. Contacting Jan is the right thing to do for clarification.
If the reference is to page 37, figure 8, then the above advise is invalid. There is no 'R6', R5 is 1K to ground, don't think R4 should be this value. There is another labeling error in the schematic, there are 2 R3's, one below J1 and one below J2.
If I read it correctly, P1 is there to balance the unmatching of J1 and J2. The unknown J3 and J4 can be something like 50R each. Remember they in are in series to each side of P1 anyway. FWIW, Jack's PCB labels both as 51R. In theory, if you have perfectly matched J1 and J2, then you can use 2 perfectly matched 500R for R3 and R4 and get rid of (jumpered) P1 🙂
Thanks, the errors were pretty confusing 😀
Sorry if I gave any wrong information with regards to the schematic on page 37.
On my schematic the information I gave was correct. Contacting Jan is the right thing to do for clarification.
No worries buddy. 🙂
if you have to regulate (as Dick has mentioned, more juice is better, so you are trading off sound quality vs the regulator's overhead), I would much prefer you use LT1963A and LT3015.
Hi Jack, thanks for Your comments. Regarding juice®ulation, I plan to use trafo with 2X18 secondaries connected in serial for one rail, so I will have plenty of juice (2X36AC) to spend 🙂. Probably overkill but why not. I prefer to have caps multiplier on board as a last power stage to vacuum all HF junk.
But be aware that with he relatively high Zout of a caps multiplier, you actually generate signal-related ripple on the supply lines due to the signal-related load current.
It is MUCH better, if you feel like you need a cap multiplier, to place it BEFORE the reg.
Jan
It is MUCH better, if you feel like you need a cap multiplier, to place it BEFORE the reg.
Jan
Thanks Jan, food for thought.
For how much rail current varies with output current in this circuit?
For how much rail current varies with output current in this circuit?
Last edited:
Thanks Jan, food for thought.
For how much rail current varies with output current in this circuit?
Depends on the Zout of the cap multiplier, which depends on the device and standing current and such.
According to Ohms law, for every ohm Zout, 1 mA load current generates 1mV ripple.
Most cap multipliers have several ohms Zout up to 10 or more.
Jan
Last edited:
> Most cap multipliers have several ohms Zout up to 10 or more.
For ~100mA DC current out ?
Patrick
For ~100mA DC current out ?
Patrick
For how much rail current varies with output current in this circuit?
Sorry Jan, maybe I put wrong question. I mean:
For how much rail current varies with input signal in this circuit?
I had an impression this circuit works mostly in class A (maybe I am wrong)?
> Most cap multipliers have several ohms Zout up to 10 or more.
For ~100mA DC current out ?
Patrick
Quick sim: BC546, 24V and 100mA DC load, almost exactly 1 ohm.
10mA load current gives 10mV ripple (1kHz sine load current).
Jan
Sorry Jan, maybe I put wrong question. I mean:
For how much rail current varies with input signal in this circuit?
I had an impression this circuit works mostly in class A (maybe I am wrong)?
Depends on the load you draw. The output voltage across the load requires a current, which has to come from the supply. Know the Vout and Zload and you know Isupply (talking about the signal only of course, not DC).
Jan
I happened to have a Spice model of a cap multiplier on hand.
At 15V 150mA DC bias, and +/-100mA 1kHz AC current draw, the ripple is 70mV pk-pk.
So that works out to be 0.35 ohm ?
Maybe 0.5 ohm if DC bias reduced to 100mA.....
But not quite 10 ohms.
Output transistor is BC550/D44H11 Darlington.
You'll kill the BC547 with 100mA.
😉
Patrick
At 15V 150mA DC bias, and +/-100mA 1kHz AC current draw, the ripple is 70mV pk-pk.
So that works out to be 0.35 ohm ?
Maybe 0.5 ohm if DC bias reduced to 100mA.....
But not quite 10 ohms.
Output transistor is BC550/D44H11 Darlington.
You'll kill the BC547 with 100mA.
😉
Patrick
I happened to have a Spice model of a cap multiplier on hand.
At 15V 150mA DC bias, and +/-100mA 1kHz AC current draw, the ripple is 70mV pk-pk.
So that works out to be 0.35 ohm ?
Maybe 0.5 ohm if DC bias reduced to 100mA.....
But not quite 10 ohms.
Output transistor is BC550/D44H11 Darlington.
You'll kill the BC547 with 100mA.
😉
Patrick
OK so maybe it's 0.5 ohms or even less. Still two orders of magnitude more than a good reg with remote sensing. My point is that I can't see why I should build a super-duper reg and then negate it with a cap multiplier after it.
Jan
PS Never ever blew up a BC547 in the sim yet; don't expect to either 😉
> My point is that I can't see why I should build a super-duper reg and then negate it with a cap multiplier after it.
HF noise ?
P.
HF noise ?
P.
But if you LP filter that twice and put it to a low noise emitter follower, you will only have the noise of the transistor.
I think John uses something similar in his commercial products.
Plus that at least for the F5 headamp, someone did have stability problems with a high NFB regulator (Salas shunt).
Not so with a cap multiplier.
Patrick
Patrick
I think John uses something similar in his commercial products.
Plus that at least for the F5 headamp, someone did have stability problems with a high NFB regulator (Salas shunt).
Not so with a cap multiplier.
Patrick
Patrick
But if you LP filter that twice and put it to a low noise emitter follower, you will only have the noise of the transistor.
Patrick
Yes but I don not believe that it would be lower than the noise of a good reg. You can use the same low noise parts in either. You would increase signal related ripple in the hope that the noise would be less - well I know what I would chose!
Plus that at least for the F5 headamp, someone did have stability problems with a high NFB regulator (Salas shunt).
Not so with a cap multiplier.
Patrick
Quite possible - the signal related ripple may, depending on phase, counteract instability if it was a result of coupling through the supply lines.
So JC uses it, right? Well that would make me suspicious 😉
jan
Yes, he uses a 317/337 followed by RC filtered follower.
Me too, for certain applications where PSRR is good.
I guess we shall always agree to disagree on this ..........
🙂
Patrick
Me too, for certain applications where PSRR is good.
I guess we shall always agree to disagree on this ..........
🙂
Patrick
Yes, he uses a 317/337 followed by RC filtered follower.
Me too, for certain applications where PSRR is good.
I guess we shall always agree to disagree on this ..........
🙂
Patrick
No I don't necessarily disagree for such a case - if PSRR is already very good, you get into the realm of diminishing returns, agree. And then a 317/337 combo with a cap multiplier will be perfect.
It's just that I don't think it is a good move to first build a superreg and then follow it with a cap multiplier.
Jan
diyaudio keantoken:
Input rejection: +66db/-54db or +2k/-500
Output impedance:
112mR at 25mA
45mR at 50mA
27mR at 100mA
20mR at 200mA
17mR at 400mA
The K Multiplier
diyaudio sikahr has made dirtyPCB för it.
//
Input rejection: +66db/-54db or +2k/-500
Output impedance:
112mR at 25mA
45mR at 50mA
27mR at 100mA
20mR at 200mA
17mR at 400mA
The K Multiplier
diyaudio sikahr has made dirtyPCB för it.
//
- Home
- Amplifiers
- Headphone Systems
- Marsh headphone amp from Linear Audio