John Curl's Blowtorch preamplifier part II

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The 9028 is not really very expensive -- only $50 1 off.
I too wonder why they didn't use the 9038 -- why not go for the best of range - even that's only $70...

The TI resampler maybe allows some marketing hype to differentiate themselves?

Well, I think I know why they used the 9028 now. I think you're going to be seeing a lot of companies use the 9028 in 2-channel applications vs the 9038, actually.

Based on some info floating around the internet, the 9038 is basically 4 of the 9028 DAC sections in parallel internally. The output current ends up being 4x that of the 9028 in any equivalent configuration. For the 9018 and 9028, if you use them as 2-channel devices, you were looking at around 15mA into the I/V converter (ignoring bias/offset current). If you use that same configuration with the 9038 you'll get 60mA out! Not easy to handle for an op-amp with a reasonably sized feedback resistor. I would be very curious to see their mono-mode application circuit. Of course, there are other ways to design the I/V converter and output circuit, but it's a bit unfriendly to the "textbook" datasheet approach.

I'm guessing the real point of the 9038 is that you can get 8-channel performance basically equivalent to the stereo performance of the 9028. I doubt anyone finds 133dB DNR insufficient.
 
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Can I inject something technical ;-) ?

Am trying to measure the input impedance of a BUF634 unity gain open loop buffer. Spec says 8meg (or 80meg, depending on bandwidth setting) // 8 pF.

Now this chip has no connection to ground, and has floating supplies bootstrapped from the output. So, how should I consider the 8pF? Model like 2 x 4 pF to each supply? If so, and the supplies are bootstrapped, would I measure no input capacitance?

The attached measurement belies that.

Jan
 

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