John Curl's Blowtorch preamplifier part II

Status
Not open for further replies.
Not when the series regulator following the shunt one is a capacitance multiplier – not as far as supply ripple is the issue. With class A amps, the extra inner impedance of the capacitance multiplier is a lesser issue than ripple value. Now, shunt regulators have benefits other than including the return in the regulating chain.

Your series reg after the shunt will be worse than the shunt - there's no improvement, max you get is same. Do the math.

jan didden
 
Jan, in the CTC Blowtorch the current changes are almost unmeasurable, because it is a class A, complementary differential folded cascode stage that forces the current to be constant at all times to a first order approximation.
 
Last edited:
Yes, the BT supply current is almost constant.
 

Attachments

  • supcurr.PNG
    supcurr.PNG
    42.4 KB · Views: 409
In a series reg, the return current goes back to a capicitor at the reg output. That means it goes through some traces or wire. This same wire or trace will carry return current from other stages or other parts of the (pre) amp. So there is coupling between stages through the voltage induced on the return leg, and that induced voltage is generally distorted, but also can be seen as part of the input signal.

In a shunt reg, the return current doesn't go back to the supply but is part of the shunt current which varies with the load current.

Yes a schematic would be nice ;-)

jan didden

Fireworks,

Are you comfortable with my explanation? If not, we can discuss this further.

jan didden
 
Thanks PMA, of course, the CTC line stage is somewhat of an exception. Many OP amps and most discrete designs would have more variation in current with audio signal.
I use the shunt regulator in the CTC primarily as a transient eliminator, as I have measured the multi-MHz bleedthrough that happens with standard IC regulators. In fact they are virtually 'AC shorts' in the MHz region. It has been shown by an IBM paper published in the IEEE a few years ago, that power line garbage can extend to 50 MHz or more, just from electric stoves, so I thought that I would cover that area as well.
 
No shunt will help at "multi-MHz bleedthrough", neither discrete based, neither opamp based with >1GHz and XXXX V/μs. When error amp run out of steam, all rejection left is based on CCS pass element. Your best friend there are small package ceramic caps & ferrite beads.
 
No shunt will help at "multi-MHz bleedthrough", neither discrete based, neither opamp based with >1GHz and XXXX V/μs. When error amp run out of steam, all rejection left is based on CCS pass element. Your best friend there are small package ceramic caps & ferrite beads.

Indeed, a shielded RF filtering at the mains entrance would be useful. One measure doesn't exclude the other, each has its' own benefits and merits.
 
John also mentioned that the folded cascode architecture was used. In most implementations of folded (shunt) cascode, the supply current is constant in instantaneous or average measurement, and this is true of SE or differential designs - again, for most implementations.

I use shunt cascode arrangement for almost all gain stages, even with triode-connected pentodes. The supply-rejection and common-mode rejection are way ahead of any other methods, and the supply current is entirely constant.
 
Stormsonic, I already use low leakage E-I transformers, a pi network composed of 3 elements, including a common mode choke, before the first regulator, but there is that area between 100KHz and 10MHz where the power most fet is still active as a shunt, working against a 10 ohm resistor. My explanation about the behavior of the standard 317-337 regulators is more for general understanding of a potential problem in a number of circuits, especially digital, not just the Blowtorch.
 
Yes, the BT supply current is almost constant.

OK, so with the 1k load, and 8V peak Vout, I would expect 8mA peak supply current variation.
Which is exactly what your sim shows.
So it appears that the supply current variation is exactly the same as the load current; in other words the load current is reflected in the supply 1:1. Whatever this circuit does, it does nothing to supress supply current variations.
Your statement that it 'does have very little supply current variation' or words to that effect is wrong.

jan didden
 
OK, so with the 1k load, and 8V peak Vout, I would expect 8mA peak supply current variation.
Which is exactly what your sim shows.
So it appears that the supply current variation is exactly the same as the load current; in other words the load current is reflected in the supply 1:1. Whatever this circuit does, it does nothing to supress supply current variations.
Your statement that it 'does have very little supply current variation' or words to that effect is wrong.

jan didden

Where have you read this?? (8mA supply current variation). It is about +/- 0.01mA. For a clever guy like you, I would assume more circuit theory understanding.
 

Attachments

  • curr.PNG
    curr.PNG
    14.8 KB · Views: 292
Status
Not open for further replies.