Geddes on Waveguides

JoshK said:
Got a fax machine Dr. Geddes? I think I have a closed form solution. I'd like you to have a look if you are interested.

I need to rewrite my work so it's legible first, but it isn't too long.

Edit: I rewrote my solution to make it somewhat legible. You can email me with your fax number if you have one and care to look.

I'd love to see it, but I don't have a FAX (kind of old fashion aren't they?) Could you just E-mail me a PDF or something in an E-mail?

egeddes@gedlee.com
 
I punched the formulas into excel last night and the cases where Theta was 60º (half coverage angle) and the exit angle (which I call alpha) is 6º the difference is pretty small ~ 2/1,000th of an inch. If Theta is 30º, the difference becomes more meaningful.

Anyway, I edited the spreadsheet so the contour is corrected for the exit angle and I just need to do some organizational work to make it user friendly. Once people have had time to double check my work and we assured its correct I'll share the spreadsheet.

Is there a better symbol than alpha to use? I am not familiar with commonly used notation.
 
Had computer problems last night and could not use my computer. Will get back to you.

Yes, the correction is small, but you also have to think of it in terms of how small the dimensions in the throat are - and the phase plug. These small errors can have a big effect in the throat. At the mouth +- .25" probably works fine.
 
Well I was posting an update on here and my computer rebooted.

Dr. Geddes and I had some back and forth discussion via email and I think we verified the solution. It reduces quite nicely.

I've update my solution to reflect the reduction and make it a bit more readable. If anyone is interested, I've attached it. I will update the spreadsheet and clean it up some and then post it.
 

Attachments

It would be quite interresting to compare these results to what John Kreskovsky has found (a spreadsheet way early in this thread) and look if they are identical. It seems he found a closed-form solution also...

- Klaus
 
Originally posted by JoshK
If anyone knows how to make a picture work for printing to real scale that would be greatly helpful.
Hell if I knew to make XL plot a graph with fixed aspect ratio...

I can only think of a crude workaround:

Screen hardcopy --> Photoshop --> correct aspect ratio from known distances in the graph --> resample with the correct DPI setting to 1:1 output from the printer

Hhm, no XL gurus here?


Ah, found the first UI bug, Josh.

Cell D10 should read "=C10*PI()/180" (entered exit angle --> transfered to radians)

First comparisons to J.K.'s *) look very good (got the same X offsets with both your and his version for some values tried). Thumbs Up!

*) Same initials, same output. More than a coincidence?

- Klaus