Hi,
I have a problem with a amp I'm building wherein the signal is heavily attenuated if I have a balance pot in the chain.
The chain is: a tone control, the balance, then an ACP+ with a 20k volume pot.
Heavily attenuated means ~1/3 the output level from the amp with the balance in the chain compared to it removed. I know the balance will attenuate a bit (and I see that when testing it in isolation), but not this much!
I've attached schematics of the tone control and balance.
I have a sneaking suspicion the problem is the impedance of the balance pot compared to the ACP's volume pot but I still haven't deeply understood the interaction of impedances practically.
I'd be grateful for ideas to fix this. I'm tempted to just build an active version (as per Doug Self's small signal book) but wonder if it could be done passively (and whether it'd help).
I have a problem with a amp I'm building wherein the signal is heavily attenuated if I have a balance pot in the chain.
The chain is: a tone control, the balance, then an ACP+ with a 20k volume pot.
Heavily attenuated means ~1/3 the output level from the amp with the balance in the chain compared to it removed. I know the balance will attenuate a bit (and I see that when testing it in isolation), but not this much!
I've attached schematics of the tone control and balance.
I have a sneaking suspicion the problem is the impedance of the balance pot compared to the ACP's volume pot but I still haven't deeply understood the interaction of impedances practically.
I'd be grateful for ideas to fix this. I'm tempted to just build an active version (as per Doug Self's small signal book) but wonder if it could be done passively (and whether it'd help).
Attachments
You have a 100k pot and 33k. The dual gang pot has to be centred (50k + 50k) for equal output from each channel. That gives around -3dB attenuation.
If you now load the wiper with the 20k volume pot you drop the level by around -8dB. If you drop the values by a factor of ten (10k pot and 3.3k) you get to around -3.5dB attenuation.
If you now load the wiper with the 20k volume pot you drop the level by around -8dB. If you drop the values by a factor of ten (10k pot and 3.3k) you get to around -3.5dB attenuation.
I did a lot of research here on balance pot but ended up just using one of these
https://partsconnexion.com/audio-note-100k-ohm-stereo-balance-potentiometer/
problem for me was solved I stopped over thinking it
https://partsconnexion.com/audio-note-100k-ohm-stereo-balance-potentiometer/
problem for me was solved I stopped over thinking it
Info here if more to your taste
I wanna advice how to make the proper way to do a balance potentiometer for audio.
I'm using 100K ladder resistor as volume control but also I use AVC.
TIA
Felipe
I'm using 100K ladder resistor as volume control but also I use AVC.
TIA
Felipe
- merlin el mago
- Replies: 18
- Forum: Analog Line Level
Thanks @Mooly. I didn't mean for this to be a tutorial on how to calculate this (which I'd like to be able to do for my understanding), but I happened on the post below (here) by you so I hope it's not too large a request to ask if you could explain...
I would think in this case I replace the 3900 Ohms with my balance pot arrangement and the 430 Ohms with my 20k pot. However, I can't reproduce the -8dB you quote with any arrangement of half-track and 33k resistances in the balance pot that occur to me. Could you explain how you got to -8dB please?
Worked out the old fashioned way.
3900 + 430 = 4330 ohms. If we apply 1 volt the current is I=V/R which is 1/4330 which is 0.2309 milliamps. Voltage across the 430 ohm is 0.2309E-3 * 430 which is 0.1 volt.
So 1 volt in and we get 0.1 volt out.
20log (Vout/Vin) gives us -20db
I would think in this case I replace the 3900 Ohms with my balance pot arrangement and the 430 Ohms with my 20k pot. However, I can't reproduce the -8dB you quote with any arrangement of half-track and 33k resistances in the balance pot that occur to me. Could you explain how you got to -8dB please?
Is that a half-track pot (i.e. for half the travel the resistance doesn't change)? The description doesn't actually say.I did a lot of research here on balance pot but ended up just using one of these
https://partsconnexion.com/audio-note-100k-ohm-stereo-balance-potentiometer/
problem for me was solved I stopped over thinking it
I didn't mean for this to be a tutorial on how to calculate this (which I'd like to be able to do for my understanding), but I happened on the post below (here) by you so I hope it's not too large a request to ask if you could explain...
Like this 😉
but that's not quite true... its much quicker like this:
Is that a half-track pot (i.e. for half the travel the resistance doesn't change)? The description doesn't actually say.
From what I understand yes
heres more about itAudio taper (logarithmic):
This design ensures a smooth and even volume change throughout the rotation of the knob, providing a more natural listening experience.
Stereo balance precision:
Designed specifically for stereo applications, it allows for accurate left-right channel balance adjustments.
a bit more about it
feature a conductive track made from thick silver, a wiper made from solid silver and heavily silver plated connection pins.
feature a conductive track made from thick silver, a wiper made from solid silver and heavily silver plated connection pins.
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