Balance pot attenuating signal

Hi,
I have a problem with a amp I'm building wherein the signal is heavily attenuated if I have a balance pot in the chain.
The chain is: a tone control, the balance, then an ACP+ with a 20k volume pot.
Heavily attenuated means ~1/3 the output level from the amp with the balance in the chain compared to it removed. I know the balance will attenuate a bit (and I see that when testing it in isolation), but not this much!

I've attached schematics of the tone control and balance.
I have a sneaking suspicion the problem is the impedance of the balance pot compared to the ACP's volume pot but I still haven't deeply understood the interaction of impedances practically.
I'd be grateful for ideas to fix this. I'm tempted to just build an active version (as per Doug Self's small signal book) but wonder if it could be done passively (and whether it'd help).
 

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You have a 100k pot and 33k. The dual gang pot has to be centred (50k + 50k) for equal output from each channel. That gives around -3dB attenuation.

If you now load the wiper with the 20k volume pot you drop the level by around -8dB. If you drop the values by a factor of ten (10k pot and 3.3k) you get to around -3.5dB attenuation.
 
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Thanks @Mooly. I didn't mean for this to be a tutorial on how to calculate this (which I'd like to be able to do for my understanding), but I happened on the post below (here) by you so I hope it's not too large a request to ask if you could explain...

Worked out the old fashioned way.

3900 + 430 = 4330 ohms. If we apply 1 volt the current is I=V/R which is 1/4330 which is 0.2309 milliamps. Voltage across the 430 ohm is 0.2309E-3 * 430 which is 0.1 volt.

So 1 volt in and we get 0.1 volt out.

20log (Vout/Vin) gives us -20db

I would think in this case I replace the 3900 Ohms with my balance pot arrangement and the 430 Ohms with my 20k pot. However, I can't reproduce the -8dB you quote with any arrangement of half-track and 33k resistances in the balance pot that occur to me. Could you explain how you got to -8dB please?
 
Is that a half-track pot (i.e. for half the travel the resistance doesn't change)? The description doesn't actually say.

From what I understand yes​

heres more about it
Audio taper (logarithmic):
This design ensures a smooth and even volume change throughout the rotation of the knob, providing a more natural listening experience.
Stereo balance precision:
Designed specifically for stereo applications, it allows for accurate left-right channel balance adjustments.
 
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