DC Servo MOSFET Amplifier

BC546 is "locked" by voltage divider consisting of 2k2 (Ube),22k and 47k. when transistor is "locked, LED in parallel with it can not light. when a voltage out of amplifier output gets higher than Ube needed to keep transistor locked,the transistor is unlocked and LED lights.
capacitor in a circuit (i believe) serves for LED to light at more severe clipping, not in short terms. it, in my opinion serves to make a clipping indication a little bit "slower".
it is just an opinion of amateur, I would also like for Mile to explain it as proper as it should be.
 
Hi Sonal,

Do you have a schematic that matches your layout? Mine is not working and I'm having trouble finding the error without the schematic.

Thanks, Terry

Mr, Mile removed clipping indicator from his original FX100 layout. I just added one of his simple clipping indicator.
 

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Hello prasi
greetings tested on 50 0 50 AC transformer i used a bigger double contact 24v
relay had to change 1K2 5 watt to 1K 5watt and as the overcurrent would kick in
early 2 .1 5watt in parallel used maybe i will try to add a better 15 volt regulated
supply using LM317T /LM337T its a very nice compact power supply
warm regards
Andrew
 
?

If Vout rises and takes the diode voltages with it, the other diode still conducts and the LED still glows.

If Vout falls to well below Pgnd, then when Vout + Vf < Vdiode+ Vled then the LED turns off.
So I ask again what does the diode to OUT do? Turn off the LED?