Yes It Can Drive An F4 -- an example circuit using tightly matched bipolar transistors

"collectorQ3 = Iemitter = (Vzener - VBE) / R6

Plugging in numbers, Icollector of Q3 works out to be approx 2.7 milliamps.

The first stage's bias current is just a resistor ratio multiplication of the reference current

IcollectorQ7 = IcollectorQ4 * (R7 / R11)

In the same exact fashion, the second stage's bias current is another resistor ratio times Ireference

IcollectorQ12 = IcollectorQ4 * (R7 / R20)"



Snipped from post #1. The same amount of current flows through Q3 and Q4 so you can just run the numbers and add up the currents for your answer.
 
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