simple quasi complimentary MOSFET amplifier BUILDERS GUIDE

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D1 and 2 = 1n4004
D4 =1n4002 why not a 1n4004 too
 

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The 1n400x x=1,2,..7 just means it has higher breakdown voltage with 7 being 1000v. The forward drop is still the same ~0.6v I think.

Hugh Dean has some different values for some of the components but that has not been tested.

Well, I am using Aksa's values and they seem to work for me. I just need to add the 220R resistor to my string since I have 500R trimmer and it should let me hit 0v. I am at -23mV but down from -2.5v before so Hugh's values have really been helpful for me. The biggest change was probably use of 1n4148 for the red LEDs.
 
Offset adjust part have design problem. to get offset near to zero, the base voltage of Q1 will be between -0.55 V to -0.65V.As per the existing design it will between-2.4 to -2.8. you cannot get zero bias. Another issue is VR1 is connected in series with led, Any change in -ve supply voltage will change offset, may be small because R6 is much higher than VR1.But sure it will change.

By very little modification you can get stable 0V offset.
 

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Sorry , Connect two red LED instead of one LED and a diode to get 0 t0 -1.2V at base of Q1. calculation mistake. Then Voltage across VR1 is -3.6V and Q1 base voltage can vary between 0 to -1.2 V
 
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