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Output impedance

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Could somebody help me with this problem, I'm just wondering what the output impedance is for the circuit beneath.

I have tried to find the formula for the output impedance, but I don't know if it's correct.

the formula I found is:

Zout= Rk || (rp+Ra+u*Rk)

or (Rk*(rp+Ra+u*Rk)) / (Rk+rp+Ra+u*Rk)
 

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Zout = Rk // [(Ra+ra)/(u+1)]

To put it in words, looking up into the anode, all resistances are divided by a factor of (u+1), and that little lot is in parallel with your cathode bias resistor.

The equation you quoted would imply that loading a cathode follower with a constant current sink insted of a cathode resistor would significantly increase its output resistance.
 
Zo AT THE CATHODE.

Hi,

The easiest way is:

Output impedance (cathode):
Rk' = (Rl+ra)/(mu+1)
Rout = Rk'||Rk

Where:

Rp = the plate resistor
Rl = the load resistance, or the input resistance of the next stage
Ra = the total load resistance, which is Rp in parallel with the input resistance of the next stage, Rl. If there is no Rl, Ra = Rp.
ra = the internal plate resistance of the tube
mu = the mu of the tube

Keep in mind this for a bypassed Rk.

Cheers,😉
 
Bypassed Rk?

Hi,

Meaning : cathode resistor bypassed with a capacitor.

Should have clarified that.

For the unbypassed common cathode circuit you can use this:

Rout = [(Ra + ra)/(mu + 1) * Rk] / [(Ra + ra)/(mu + 1) + Rk]

Where:

Rk = the cathode resistor
Ra = the total load resistance, which is Rp in parallel with the input resistance of the next stage, Rl. If there is no Rl, Ra = Rp.
ra = the internal plate resistance of the tube
mu = the mu of the tube

Cheers,😉
 
I SEE.

Hi,

Sorry if I got anyone confused here.😱

Output impedance (cathode):
Rk' = (Rl+ra)/(mu+1)
Rout = Rk'||Rk

Actually this is the output impedance calculated for a common cathode stage,signal is of course taken from the plate,cathode R is bypassed.

Output impedance (plate):
Rout = (ra * Rp)/(ra + Rp)

Hope this sets it straight.

Cheers,😉
 
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