Newbie with a plan! (good or bad you decide!)

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You see from the german project that the mids and the tweeters have both an attenuation net -the resistors before the drivers ( L-pads). I see only one resistor in your X-over.
So there comes the basic understanding of how a crossover is made in order to split frequencies, equalize according to the SPECIFIC driver that it is chosen.
In other words, you might replicate the x-over part for the mid&tw -which is hard ( wire diameter in inductors plays a role ) and choose a woofer that AFTER the lowpass and in-cab positioning, would exhibit same efficiency. That's the role of simulation, to make decisions before any purchase to make the project fit the goals.
 
I you choose double-woofers-arrangement and the woofers are nominal 8Ω, you'll encounter more troubles 'cos you'll have discrepancy in the impedance curve and that, amplifiers don't like ( at high power, though ).
I see an impedance flattening net at the beginning of the german project, it must be there for a reason ?!?
 
I dunno: it's more that 20 years that I play with these things and I'm still a newbie !!
For my taste, a single 8" is more than enough: it's too big !
But, for starting, you haven't answered to the question: can you replicate the mid and tw section of the existing crossover ( well, also the low section if you use a single 8 Ω driver)
?? Don't mind about the L-pads, they can be omitted when you find the tonal balance in your room.
 
But you can...except you must build the crossover yourself.

Here's a model similar to yours:
boxsim-db.de | Boxsim Projektdatenbank
This goes in the projekte folder of Boxsim.
Downloads
Two questions related to the circuit diagram for the linked Olymp Mk II:

  1. There are two resistors across the tweeter - one of 3.3Ω and one of 2.2Ω - why not a single 5.5Ω resistor? Is this value not manufactured?
  2. Whose daft idea was it to replace the good old entirely self-explanatory "wavy wire" symbol for resistance with an "empty box" symbol? The same goes for inductors which have morphed from a "coil" into an "empty box". PC gone mad!
CircuitDiagramSymbols.jpg
 
There are two resistors across the tweeter - one of 3.3Ω and one of 2.2Ω - why not a single 5.5Ω resistor? Is this value not manufactured?
AFAIK there isn't a 5R5 resistor and the nearest standard value is 5R6. What the designer don't seem to understand is the concept of tolerance. Using a 5R6 resistor instead of the calculated 5R5 means an error of less than 2%, but OTOH a standard ceramic resistor has a tolerance of 5%, so using the 2R2+3R3 resistors hoping to get precisely 5R5 is stupid, it is way better to use only one 5R6 resistor.

Ralf
 
Ok so can anybody build me a crossover suitable for this speaker if I replace all the components??

Pleeeeeeeeeeeeeeeease 🙂

I don't think you were getting what everyone was trying to tell you. You can't go to the crossover store and buy a "3 way for dual woofers crossover". A crossover must be custom designed for the set of drivers chosen and the box they are mounted on. A generic crossover would give very poor performance because it can't take into acount the particular parameters and response of your randomly chosen drivers.

Once you ditch the drivers and crossover of the original design the only answer is a full new design starting from scratch with measurements of the new drivers on the old cabinet.
 
True enough. I had a look at a generic 3 way crossover:
HW 3/120 NG - 8 Ohm

It needed capacitor value changes plus lots of resistors added for this application, even assuming my modelling was vaguely correct.

Visaton do kits with particular drivers in particular enclosures:
3-Way Speakers

And appropriate crossovers:
Crossovers for speaker kits

But Steve has made no effort to read some simple values off the crossover board for me. So even if we wanted to just replace the woofers and tweak it, I'm stuck really. Wasted my time, if you like. 😱
 
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