"Lehmann" Buffer Output Transistors.

I have a question about the BD139 & BD140 output devices in the Lehmann buffer circuit below.

The schematic calls for the BD139 & BD140-16 devices which have the highest hFE.

What happens if you substitute the lower hFE devices like the BD139 & BD140-6 or -10?

Thank you...
 

Attachments

  • Lehmann-Headphone-Buffer.png
    Lehmann-Headphone-Buffer.png
    116.9 KB · Views: 803
  • BD140_hFE.png
    BD140_hFE.png
    75.2 KB · Views: 720
Hi,

the BC drivers are biased just under 10mA, which is quite a lot.
even if the BDs were runnung on 100mA of bias current they´d require less than 1mA of Base current.
So nothing to worry about.
THD may rise a bit with lower hfe BDs but on a rather negligable niveau.

This Buffer is the second simplest form of an Diamond Buffer.
The drivers run on ~9mA bias, the outputs on 40-45mA.
Heat power loss of the BCs is ~140mW and ~550mW for the BDs.

THD improves when You connect V12´s collector to V10´s emitter and V9´s collector to V11´s emitter.
Also the driver´s losses reduce considerably down to ~10mW, allowing for SMDs.
The BD´s power losses incerease though by ~100mW to 650mW.

jauu
Calvin
 
  • Like
Reactions: jan.didden
What happens if you substitute the lower hFE devices like the BD139 & BD140-6 or -10?
Base current for these transistors comes through the 1k5 resistors. So when the output swings close to the supply rail, voltage across these resistors is reduced, and available base current is reduced, which reduces output current capability. So, using lower hFe transistors will reduce output voltage swing in a low impedance load. You can calculate by how much depending on load impedance and therefore output current. With 600 ohms headphones, the effect is likely to be absolutely negligible.