# JLH output stage

Status
This old topic is closed. If you want to reopen this topic, contact a moderator using the "Report Post" button.

#### sajti

I found this output stage in JLH's book. But something is strange for me: What is the current of MJE15033s, if the output stage has 100mA bias?

sajti

#### Attachments

• jlh_out.jpg
19.4 KB · Views: 616

#### Jan Dupont

6 mA + the Base Current to the output device I would Guess by calculating in my head.......

#### sajti

ACD said:
6 mA + the Base Current to the output device I would Guess by calculating in my head.......

And in this case what is the current of the BDs?

sajti

#### sajti

My calculation is the following:

The current over R3 is ~6mA, due the output devices are open.But the current over R5 must be ~6mA as well. Because if it less, than the MJE-s are switched off. So I think that the current over the MJEs is equal with the base current of the output devices. Is it OK?

sajti

#### Jan Dupont

You have to take the BD's into the calculation...
I have never tried this output stage, but the BD's can feed the Bases of the MJL's directly.......

#### sajti

Of course, but not 6 pairs of MJLs for 2ohms... So I think that I will try to reduce R3 and R4 to 22ohm, to get bias for the MJEs.

sajti

#### Jan Dupont

Why ??
Only result would be to drive the driver and predriver harder ??
The total Base Current to 6 MJL's at 100mA idle would be app. 20 mA. That would be total app. 26 mA with R3=100R but 47mA with R3=22R.....

#### sajti

I plan to use it with valve VAS, so I need triple darlington to get high input impedance.
I have lot of MJE15032/33, but I was not able to select NPN/PNP pairs, because the '33s have much higher B. So I try to find output stage with same polarity driver, and output

sajti

#### sajti

ACD said:
Why ??
Only result would be to drive the driver and predriver harder ??
The total Base Current to 6 MJL's at 100mA idle would be app. 20 mA. That would be total app. 26 mA with R3=100R but 47mA with R3=22R.....

Yes, but the base current of the output devices is not well defined. And the lower value resistor result faster switch of for the output devices. With 100ohms, and 6 pairs the output stage will be 6 times slower..

sajti

#### Jan Dupont

Yes, but the base current of the output devices is not well defined. And the lower value resistor result faster switch of for the output devices. With 100ohms, and 6 pairs the output stage will be 6 times slower..

The Base Current are as well defined as on all other transistors ?
Hfe 25 to 75.....
What do yoy meen by slower ?

#### sajti

No, but the current over the resistor is well defined. I want to define the bias current over the driver.

The charge of the base capacitance of the output devices will be discarged across the base resistor. Lower value base resistor makes the switch of faster. I think You use low value resistor in Your Linx amp...

sajti

#### Jan Dupont

Yes that's right that I use low value resistors in my LYNX Amp
But not for that reason....

But the MJL's are 4 MHz devices, so they are not slow in the very slow device section

#### sajti

Not for that reason, but low value resistor will for switch off too. There will be no cross conduction with high frequency squarewave signal.

The MJLs are 4MHz devices. But if You have to help them to be as fast as they can.

sajti

#### Jan Dupont

And how will you get a high frequency square wave signal out of your valve VAS to feed into the MJL's ?

#### sajti

The driver use low impedance stages, with direct coupling, and White follower to drive the BJTs

sajti

Ok

#### lumanauw

Hi, Sajti,

I'm just thinking a simple modification, will it make a better performance?
The emitors of BD139/BD140, don't connect them to collectors of MJE15032/MJE15033.
Put new RE from emitors of BD139-BD140 directly to output node (junction of 0.22's). This shifts the function of BD139-BD140 to local CFB output stage.

#### sajti

Would You make a drawings?

sajti

#### lumanauw

Something like this :
It makes the BD139-BD140 not controlling CFP, but controlling a local loop CFB output stage.

#### Attachments

• sajti.jpg
79.5 KB · Views: 378

#### linuxguru

Yup, that will work. If you perform some more circuit elaboration, you can get to Edmond's error-correcting output stage, or to my Kulish-corrected output stage.

Status
This old topic is closed. If you want to reopen this topic, contact a moderator using the "Report Post" button.