If you look at the pictures at post 167 and 179, there you have the answer. The outline of the part is not maybe optimal in clearness but since you both have schematics, pcb layout and on top of that a double sided board it's possible to figure out the correct placement.
If you look in the schematics you'll see that the LED is twisted 180 degrees compared to the normal zener diode. I use the LED as a 1.6 V zener.
If you look in the schematics you'll see that the LED is twisted 180 degrees compared to the normal zener diode. I use the LED as a 1.6 V zener.
THANK YOU!
Now I get +-5V
It was the DZx LED.
plugged 10ohm / 10W load restisors to emulat 500mA@5V
I measure 3,26V instead of 5V
During the load test the DZx LED didn't show any light
Now I get +-5V
It was the DZx LED.
plugged 10ohm / 10W load restisors to emulat 500mA@5V
I measure 3,26V instead of 5V
During the load test the DZx LED didn't show any light
In general: To use a second resistor at R47+48 I can use the R49+50 pads?The current limitation must be set to cover your needs. R47 and R48 must be tuned. 0.65/I = R
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The current limitation must be set to cover your needs. R47 and R48 must be tuned. 0.65/I = R
350 mA = 1.8 ohm
If you solder 12 ohms in parallel, then you will have 1.8 ohms. You can remove the 2.2 ohm and replace it with 1.8 ohm but the risk is that you will damage the pcb.
According to the formular I have to use:
1,3ohm for 500mA@5V
1,625ohm for 400mA@17V
2,6Ohm for 250mA@15V; this is fine with the orig. configuration of 2,2ohm.
you mean 12 ohm parallel to the existing 2,2 ohm ;-)
then R49+50:
3,3ohm to get 490mA@5V
6,8ohm to get 390mA@17V
right?
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You should use the law of parallel connection. Easy to find on the net if you don't know it by heart.
A = the shunt you have
B= resistor to add
C= wanted total resistance
B = 1/((1/C)-(1/A))
or
B= (A*C)/(A-C)
A = the shunt you have
B= resistor to add
C= wanted total resistance
B = 1/((1/C)-(1/A))
or
B= (A*C)/(A-C)
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66% is done
I soldered 6,8ohm resistors at R49+50 paralell to the existing 2,2ohm at R47+48
both 17V-SSR03 measured 2x 17V with installed load resistors ;-)
the 5V SSR03 seams to be more complicate..
I soldered 3,3ohm resistors at R49+50 paralell to the existing 2,2ohm at R47+48
the results at X3 are -3,76V +3,9V with installed 10ohm/ 10W load resistors
During the load test all LED just flashes a short time
the results at X3 are +-5V without installed load resistors
During this test all LED are on
I soldered 6,8ohm resistors at R49+50 paralell to the existing 2,2ohm at R47+48
both 17V-SSR03 measured 2x 17V with installed load resistors ;-)
the 5V SSR03 seams to be more complicate..
I soldered 3,3ohm resistors at R49+50 paralell to the existing 2,2ohm at R47+48
the results at X3 are -3,76V +3,9V with installed 10ohm/ 10W load resistors
During the load test all LED just flashes a short time
the results at X3 are +-5V without installed load resistors
During this test all LED are on
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317, plan view, from right to left, without installed load resistors
11,32
7,57
6,33
337, plan view, from right to left,without installed load resistors
7,29
11,28
6,04
11,32
7,57
6,33
337, plan view, from right to left,without installed load resistors
7,29
11,28
6,04
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I'm interested with load. Without load you have a correct function as you have noticed. The task now is to determine why you have the voltage drop.
317, plan view, from right to left, with installed load resistors
4,41
5,47
5,08
337, plan view, from right to left,with installed load resistors
5,45
7,38
4,88
4,41
5,47
5,08
337, plan view, from right to left,with installed load resistors
5,45
7,38
4,88
You should have 10 volts at least and the real value is only 5,4 volts
Do you have 2,2 ohm at R1-R10?
Can you please check:
AC voltage between X1, 1 and X1,2?
DC voltage from both sides of R9 down to ground?
Maybe your R1-R10 has to high values for your needs.
Do you have 2,2 ohm at R1-R10?
Can you please check:
AC voltage between X1, 1 and X1,2?
DC voltage from both sides of R9 down to ground?
Maybe your R1-R10 has to high values for your needs.
load resistors installed
I do measure 2,4-2,5 ohm at R1-10. In installed condition.
AC1+2 are 8,5V AC
AC1 - AC2-gnd and vis versa is also 8,5V AC
8,28V R9 7,28V DC
I do measure 2,4-2,5 ohm at R1-10. In installed condition.
AC1+2 are 8,5V AC
AC1 - AC2-gnd and vis versa is also 8,5V AC
8,28V R9 7,28V DC
The series resistors are a bit too high when you have 8,5 VAC in. Try to reduce R1-R8 to 1 ohm. If that doesn't help reduce R9 and R10 also.
Bought 1ohms Burt measured 1,2ohms...
Installed one side R4-10, measured 4,2v@x3
Second side just r5+7, measured 3,6v@x3
Load resistors installed
Installed one side R4-10, measured 4,2v@x3
Second side just r5+7, measured 3,6v@x3
Load resistors installed
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Don not get it wrong. The 10V findings are now a few weeks too late. I was afraid of that during the last few days.... Before I ordered this individuall made transformer, I asked you about it. You said 9V are OK. Well, it's 8.5V now...
The resistances, as they are given, certainly have a meaning? Is shorting all resistors to get a result? Or are the parts on the place not this important?
The resistances, as they are given, certainly have a meaning? Is shorting all resistors to get a result? Or are the parts on the place not this important?
The resistors are for reducing harmonics. Normally you don't have any but this is a super regulator with ultra smooth raw voltage.
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