Hello,
I've played with electronics for a while now, building tube amplifiers and stompboxes.
Now I'm in need to build a couple of battery guitar amps for me and a friend to go out in the street!
I've looked around for quite a while and I've seen some really different (sometimes opposite) comments on which chip to use. That's why I write you here.
All the project is on a tight budget!
The speaker will probably be a 10" 35w 8ohm 95dbm
I'm searching for an IC with the following characteristics:
- not SMD (I won't be able to solder it)
- quite efficent (first idea was obviously class D/T but seems that all the IC's are SMD :-( )
- not too current ungry (to save battery life)
- can deliver around 10W (I think it will be plenty of power for busking, we need to be heard, we don't want to impose)
Until now I'm looking into the TDA2005 and TDA7396.
Anyone know if they will fit my needs or have a better idea?
aaand time for noob question:
How can I have a approximate idea of how much current the chip will require for a "normal" operation? of course we got quiescent current, but the rest?
Thank you all and have a good day
I've played with electronics for a while now, building tube amplifiers and stompboxes.
Now I'm in need to build a couple of battery guitar amps for me and a friend to go out in the street!
I've looked around for quite a while and I've seen some really different (sometimes opposite) comments on which chip to use. That's why I write you here.
All the project is on a tight budget!
The speaker will probably be a 10" 35w 8ohm 95dbm
I'm searching for an IC with the following characteristics:
- not SMD (I won't be able to solder it)
- quite efficent (first idea was obviously class D/T but seems that all the IC's are SMD :-( )
- not too current ungry (to save battery life)
- can deliver around 10W (I think it will be plenty of power for busking, we need to be heard, we don't want to impose)
Until now I'm looking into the TDA2005 and TDA7396.
Anyone know if they will fit my needs or have a better idea?
aaand time for noob question:
How can I have a approximate idea of how much current the chip will require for a "normal" operation? of course we got quiescent current, but the rest?
Thank you all and have a good day
The most common type is here; Audio Amplifier ICs | RS Components
The current used will depend directly on how loud you have it. Take a look at the application note http://www.alldatasheet.com/datasheet-pdf/pdf/25044/STMICROELECTRONICS/TDA2030A.html
Hope that helps
The current used will depend directly on how loud you have it. Take a look at the application note http://www.alldatasheet.com/datasheet-pdf/pdf/25044/STMICROELECTRONICS/TDA2030A.html
Hope that helps
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TPA3125 is what you are looking for:
Class-D-Amp with quite low power consumption, in a DIP-case.
It was my first attempt to a battery amp and did quite a nice job!
Class-D-Amp with quite low power consumption, in a DIP-case.
It was my first attempt to a battery amp and did quite a nice job!
Hi,
There are loads of car type chips (BTL) that will give
about 10W into an 8 ohm load off a 12V battery.
rgds, sreten.
There are loads of car type chips (BTL) that will give
about 10W into an 8 ohm load off a 12V battery.
rgds, sreten.
Thank you for your answers.
So I looked over the two chips and I'm trying to lay down the building blocks. The first thing that I'm missing is the input sensitivity (altough on the TDA2030a there's a little reference) that I'll need as a parameter to design the preamp.
After some thinking I came up with the following:
I'll follow the signal backwards and calculate the values.
Knowing the output power and the load I can calculate the output voltage.
Knowing the output voltage and gain I can calculate the input voltage.
so If I want 8W over 8ohm there will be 8V (P=V^2 /R).
having a gain of 20db (10fold voltage) the input is 800mV.
(that in an ideal world)
Does that make sense or not at all?
p.s. should I open a new thread for further questions?
Have a nice day!
Patrizio
So I looked over the two chips and I'm trying to lay down the building blocks. The first thing that I'm missing is the input sensitivity (altough on the TDA2030a there's a little reference) that I'll need as a parameter to design the preamp.
After some thinking I came up with the following:
I'll follow the signal backwards and calculate the values.
Knowing the output power and the load I can calculate the output voltage.
Knowing the output voltage and gain I can calculate the input voltage.
so If I want 8W over 8ohm there will be 8V (P=V^2 /R).
having a gain of 20db (10fold voltage) the input is 800mV.
(that in an ideal world)
Does that make sense or not at all?
p.s. should I open a new thread for further questions?
Have a nice day!
Patrizio
You'll need to include a guitar preamp or use a active DI unit to boost the voltage to line-level, because that's what chipamps need.
Something like this FET preamp looks nice with the tone controls. Make sure to decouple the chipamp from the pre-amp.
Something like this FET preamp looks nice with the tone controls. Make sure to decouple the chipamp from the pre-amp.
Something like little power amp module may be a good start.
http://www.altronics.com.au/p/k6066-7-watt-champion-amplifier-kit/
15 bucks australian - 7 watts peak which would be plenty for busking.
Cheers,
Ian
http://www.altronics.com.au/p/k6066-7-watt-champion-amplifier-kit/
15 bucks australian - 7 watts peak which would be plenty for busking.
Cheers,
Ian
Gingertube, thank you for the link, I will keep it as a failsafe!
Erikb, thank you for your reply and link. I know that I'll need a preamp and I was planning on adding some eq (i found somewhere a really useful program for that).
I'm not trying to reinvent the wheel, but I'll like to know how to estimate voltages and gain needed.
Looking at tje Tpa3125 datasheet a little more carefully I realised my previous post is wrong!
But how much input voltage wants to develop 8w and before overloading?
Erikb, thank you for your reply and link. I know that I'll need a preamp and I was planning on adding some eq (i found somewhere a really useful program for that).
I'm not trying to reinvent the wheel, but I'll like to know how to estimate voltages and gain needed.
Looking at tje Tpa3125 datasheet a little more carefully I realised my previous post is wrong!
But how much input voltage wants to develop 8w and before overloading?
In reality the audible difference between 5 and 10W is pretty small, so it does not make much sense being precise with amp wattage.
If you power a full brigde amp (like TPA3125 or myriads of others) by a 12V SLA you can expect something between 5~10W of undistorted power at 8ohm speaker.
If you power a full brigde amp (like TPA3125 or myriads of others) by a 12V SLA you can expect something between 5~10W of undistorted power at 8ohm speaker.
You can try CS6A4983, that can deliver 8WRMS with two 9V batteries and a 4ohm speaker.
Linear current assisted Class A operation with very low current consumption that it can run at 8WRMS with the two 9V batteries for more than 6 hours depends on if you have a normal or alkaline battery.
Linear current assisted Class A operation with very low current consumption that it can run at 8WRMS with the two 9V batteries for more than 6 hours depends on if you have a normal or alkaline battery.
You can try CS6A4983, that can deliver 8WRMS with two 9V batteries and a 4ohm speaker.
Linear current assisted Class A operation with very low current consumption that it can run at 8WRMS with the two 9V batteries for more than 6 hours depends on if you have a normal or alkaline battery.
haha, obviously you are confusing rms power with pmpo🙄
two 9V batteries means +/-9V supply.
The amplifier can achieve a maximum output of +/-8V, i.e. 16Vpp
the RMS output at 4ohm load is 16*16/(4*8) = 8WRMS.
You may want to check your own math
The amplifier can achieve a maximum output of +/-8V, i.e. 16Vpp
the RMS output at 4ohm load is 16*16/(4*8) = 8WRMS.
You may want to check your own math
Thank you Voltwide. But that doesn't answer my question.... Or Yes?
When I say input voltage is the guitar signal coming from the preamp (that I have yet to "design").
Maybe I'm asking something really obvious and I came up with an idea (I more or less understand the process of class D amplification but not really what every component in the chip do) :
Is it possible that the chip (like a Tpa3125)"doesn't care" too much about the signal voltage as long as it stay between the maximum allowable (for the Tpa3125 is - 0,3 - 7v)? And that you just set the supply voltage and gain?
Sorry I don't want to sound pedantic.
Thank you!
Have a nice evening
When I say input voltage is the guitar signal coming from the preamp (that I have yet to "design").
Maybe I'm asking something really obvious and I came up with an idea (I more or less understand the process of class D amplification but not really what every component in the chip do) :
Is it possible that the chip (like a Tpa3125)"doesn't care" too much about the signal voltage as long as it stay between the maximum allowable (for the Tpa3125 is - 0,3 - 7v)? And that you just set the supply voltage and gain?
Sorry I don't want to sound pedantic.
Thank you!
Have a nice evening
two 9V batteries means +/-9V supply.
The amplifier can achieve a maximum output of +/-8V, i.e. 16Vpp
the RMS output at 4ohm load is 16*16/(4*8) = 8WRMS.
You may want to check your own math
Hi,
Lousy maths / physics but the right answer [(8 x 0.707) squared]/4 = 8.
rgds, sreten.
They are just the same
(Vp*0.707)^2 = (Vp/sqrt(2))^2 = (Vpp/(2 x sqrt(2))^2 = Vpp^2/8
and used in so many textbook....don't understand what makes it lousy?
(Vp*0.707)^2 = (Vp/sqrt(2))^2 = (Vpp/(2 x sqrt(2))^2 = Vpp^2/8
and used in so many textbook....don't understand what makes it lousy?
They are just the same
(Vp*0.707)^2 = (Vp/sqrt(2))^2 = (Vpp/(2 x sqrt(2))^2 = Vpp^2/8
and used in so many textbook....don't understand what makes it lousy?
I think more he means a standard 9V battery is 500mA/hr capacity. Even if the voltage did not sag (it does) that's 4.5W/hr X 2 = 9W/hr not 48W/hr.
Thank you Voltwide. But that doesn't answer my question.... Or Yes?
When I say input voltage is the guitar signal coming from the preamp (that I have yet to "design").
Maybe I'm asking something really obvious and I came up with an idea (I more or less understand the process of class D amplification but not really what every component in the chip do) :
Is it possible that the chip (like a Tpa3125)"doesn't care" too much about the signal voltage as long as it stay between the maximum allowable (for the Tpa3125 is - 0,3 - 7v)? And that you just set the supply voltage and gain?
Sorry I don't want to sound pedantic.
Thank you!
Have a nice evening
You do not have to care for the details of a specific class-d-amp
the wattage is a matter of battery voltage, impedance and half/full bridge topoly.
Assuming 12V supply and a gain of 20dB (10x), full bridge topology:
Output swing is <12Vpp * 2
Input level for clipping thus is 24Vpp/10 = 2,4Vpp i.e. approx 1Vrms.
So if you pre-amp delivers more output voltage, the power amp is overdriven.
Depending on your speaker this may sound more or less awful.
But no prob as long as kept insde the allowed range.
To make things simple I state any pre-amp supplied with 9~12V will do the job.
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two 9V batteries means +/-9V supply.
The amplifier can achieve a maximum output of +/-8V, i.e. 16Vpp
the RMS output at 4ohm load is 16*16/(4*8) = 8WRMS.
You may want to check your own math
Your math is based on the false assumption that 2 9V-blocks can deliver 2x9V into 8W load for a significant time.
1) 9V batteries are some of the most inefficient sources to power amps of significant wattage.
2) The proposed linear amp is not first choice for battery operations, simply because of low efficiency at low to medium output levels. For longest possible battery life class-d amp are superior.
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if you want to know how can a standard 9V battery with 500mAh can deliver the desired audio power, you can watch the following youtube
https://www.youtube.com/watch?v=ZBeniBaiUFw
which shows the very high power efficiency of the current assisted linear amplifier.
https://www.youtube.com/watch?v=ZBeniBaiUFw
which shows the very high power efficiency of the current assisted linear amplifier.
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