I want to build a bass horn a la scala. But with the 15pr400 like Volti audio.
It (15pr400) mostly needs a bigger doghouse. So I was thinking 20 percent bigger la scala all round. Perhaps also with a bass reflex mod as well. As is now 'standard' on the AL6 model.
I guess I have to learn to use hornresp?
It (15pr400) mostly needs a bigger doghouse. So I was thinking 20 percent bigger la scala all round. Perhaps also with a bass reflex mod as well. As is now 'standard' on the AL6 model.
I guess I have to learn to use hornresp?
Alright — let’s calculate the new horn mouth area, throat area, and cutoff frequency when scaling up the La Scala by 20%.
So:
≈ 0.576 m² ≈ 6.2 ft²
That’s about 30″ × 30″.
≈ 0.0288 m² ≈ 44.7 cm² ≈ 6.9 in²
The approximate formula is:
where (speed of sound).
If you scale the mouth area by , the cutoff scales as:
So:
✅ After scaling up the La Scala by 20%, you get:
ChatGPT...
📐 1. Assumptions about the original La Scala
- Horn path length ≈ 2.6 m (102″)
- Mouth area ≈ 0.4 m² (4.3 ft² ≈ 24″×24″)
- Throat area ≈ 0.02 m² (about 3 in²)
- Cutoff frequency ≈ 104 Hz (theoretical)
(This is derived from the mouth area.)
Code:
s = 1.20
📐 2. New horn path length
Already calculated:
Code:
2.6 \, m \times 1.20 = 3.12 \, m
📐 3. New mouth area
Area scales with the square of the linear scale:
Code:
A_\text{new} = A_\text{original} \times s^2
Code:
0.4 \, m² \times (1.20)^2 ≈ 0.4 \times 1.44 ≈ 0.576 m²
That’s about 30″ × 30″.
📐 4. New throat area
Similarly:
Code:
0.02 \, m² \times (1.20)^2 ≈ 0.0288 m²
📐 5. New cutoff frequency
Horn cutoff frequency depends inversely on the mouth size.The approximate formula is:
Code:
f_c ≈ \frac{c}{2\pi} \sqrt{\frac{\pi}{A_\text{mouth}}}
If you scale the mouth area by , the cutoff scales as:
Code:
f_{c,\text{new}} = \frac{f_c}{s}
Code:
104 Hz / 1.20 ≈ 87 Hz
📋 Final Results:
Parameter | Original | Scaled ×1.2 |
---|---|---|
Horn path length | 2.6 m (102″) | 3.12 m (122.4″) |
Mouth area | 0.4 m² | 0.576 m² (6.2 ft²) |
Throat area | 0.02 m² | 0.0288 m² |
Cutoff frequency | ~104 Hz | ~87 Hz |
✅ After scaling up the La Scala by 20%, you get:
- ~22″ longer path
- ~44% larger mouth and throat areas
- ~17 Hz lower cutoff frequency (~87 Hz instead of ~104 Hz)
ChatGPT...
How in all the world do you come to a horn path length of 2.6m in a La Scala ?
It is much less than half of that actually.
If this were correct the following would happen:
2.6m combined with your throat and mouth area would give a horn-constant based cutoff frequency of 31 Hz for the original and 27 Hz for the enlarged one. Since the throat area would be much too small for that the frequency response would be very irrgular.
But since your path lengts are way off this will not happen that way.
Regards
Charles
It is much less than half of that actually.
If this were correct the following would happen:
2.6m combined with your throat and mouth area would give a horn-constant based cutoff frequency of 31 Hz for the original and 27 Hz for the enlarged one. Since the throat area would be much too small for that the frequency response would be very irrgular.
But since your path lengts are way off this will not happen that way.
Regards
Charles
Chatgpt came up with those number...it summed left and right. So I asked it and now says it's around 1.70cm
I strongly recommend that you only use AI for topics that you know enough about so that you can check for yourself whether what the AI claims is true. AIs are otherwise all kinds of things, but they are not reliable sources of information.
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