9 volt DC to 48V DC

Status
Not open for further replies.
5 batteries is an option, but since the microphone only needs 2 ma of current at 48V I thought that if the circut is not very complex, it could end up being more compact that a set of 5 batteries.
Weight is another problem. This microphone feeds a camcorder in a Steady cam mount, so weight is of outmost concern.

cheers

Ric

PD: tks for the links, folks.
 
Hi,

almost all electret mikes (I suppose that's what you've got since it needs only 2mA) work with smaller voltages. Try yours with two 9V block batteries and, say, 2k2 1% resistors. Also, you might want to bypass batteries with small block caps.

Regards,
Milan
 
Re: One approach

thespeakerguy said:
use a MAX1771. It's not the latest/greatest, but will work, has a free sample, and come in an 8-pin DIP package.


Tks for the data. I never used such that chip. I downloaded the PDF and it suggests this:

"The MAX1771 drives an external N-channel MOSFET switch, allowing it to power loads up to 24W. If less power is required, use the MAX756/MAX757 or MAX761/MAX762 step-up switching regulators with on-board MOSFETs"

Which I thing is better because is more compact and I need a few MA anyway. But I can not find any reference that points at using these chips in a 48V output configuration. Any ideas?

tks, Ric
 
Status
Not open for further replies.