By all accounts that is a very nice amp and well documented so even a rookie can successfully assemble it.
But that was not what i refered to… he did a mass corner calculation that ddetermined an optimum range for the output impedance (wild guess), 1.5-2.5 Ω
dave
But that was not what i refered to… he did a mass corner calculation that ddetermined an optimum range for the output impedance (wild guess), 1.5-2.5 Ω
dave
Don't understood why damping factor = 1 4ohms is not VERY low....
Because very low is much less than 1. ie output impedance greater than speaker impedance.
dave
So if an amp have 16ohms speakers terminals, this is a good indicative that the amp have a low damping factor, or this not makes sense?
And still trying to understand, why on the ps audio damping factor spec, is just an alone number... no ohms..
This has been explained to you before as I recall. Damping factor is a unitless (and in my view rather useless) measurement which is taken as the load impedance [Zl] in ohms divided by the output impedance of the source [Zs] in ohms.
In other words, look at the impedance plot of your loudspeaker and pick its lowest point. That is Zl. Divide that by the output impedance of your amplifier and you get a number for the unitless Damping Factor [DF].
Say your loudspeaker's lowest impedance is 3.6ohms, and your amplifier has an output impedance of 2.4ohms. Therefore since DF = Zl/Zs
DF = 3.6 / 2.4
DF = 1.5
In other words, look at the impedance plot of your loudspeaker and pick its lowest point. That is Zl. Divide that by the output impedance of your amplifier and you get a number for the unitless Damping Factor [DF].
Say your loudspeaker's lowest impedance is 3.6ohms, and your amplifier has an output impedance of 2.4ohms. Therefore since DF = Zl/Zs
DF = 3.6 / 2.4
DF = 1.5
So if an amp have 16ohms speakers terminals, this is a good indicative that the amp have a low damping factor, or this not makes sense?
Not especially, it just means it has nominal 16ohm output taps. This is not the same as output impedance or damping factor.
This has been explained to you before as I recall. Damping factor is a unitless (and in my view rather useless) measurement which is taken as the load impedance [Zl] in ohms divided by the output impedance of the source [Zs] in ohms.
In other words, look at the impedance plot of your loudspeaker and pick its lowest point. That is Zl. Divide that by the output impedance of your amplifier and you get a number for the unitless Damping Factor [DF].
Say your loudspeaker's lowest impedance is 3.6ohms, and your amplifier has an output impedance of 2.4ohms. Therefore since DF = Zl/Zs
DF = 3.6 / 2.4
DF = 1.5
Now I understood! 👍
What I not understood yet is, how to know if the damping factor of an amp, is too high for the fostex fe208Ez, or is optimum?
What GM said.
By my lights, you need an amplifier with an output impedance of 3.5ohms [minimum] - 8ohms. So the Luxman mentioned with its DF of 1 should be OK, assuming 14AWG or a smaller gauge speaker wire (as Dave mentions).
By my lights, you need an amplifier with an output impedance of 3.5ohms [minimum] - 8ohms. So the Luxman mentioned with its DF of 1 should be OK, assuming 14AWG or a smaller gauge speaker wire (as Dave mentions).
I would like to try an analogy to test my understanding of Qts and output impedance. Feel free to make suggestions.
A speaker driver is like a race car, taking corners really fast. Of course, it has to have just the right amount of brakes applied, or else it will either crash or go too slow. Well, between the amp and the driver, the job of braking is split up. If the amp is solid state, it has hardly any brakes (low output impedance), so most of the braking has to be done by the driver (high Q). If the amp is of the SET type, it has great big strong brakes (high output impedance), so very little braking needs to be done by the driver (low Q).
A speaker driver is like a race car, taking corners really fast. Of course, it has to have just the right amount of brakes applied, or else it will either crash or go too slow. Well, between the amp and the driver, the job of braking is split up. If the amp is solid state, it has hardly any brakes (low output impedance), so most of the braking has to be done by the driver (high Q). If the amp is of the SET type, it has great big strong brakes (high output impedance), so very little braking needs to be done by the driver (low Q).
it has hardly any brakes (low output impedance), so most of the braking has to be done by the driver (high Q). If the amp is of the SET type, it has great big strong brakes (high output impedance), so very little braking needs to be done by the driver (low Q).
This part should be, a low output impedance amp is expected to supply almost all the damping — all electrical -- as the output impedance increases the speaker/box need to provide more of the damping.
Note that the Q of interest is the Qm (mechanical), usually you want the Qm to get closer and closer to flat, but it isn’t just that, because the Fostex FExx6 have fairly high Qm.
Then one has to talk about the change/increase in Qt when output impedance climbs and how that changes the mass corner (an important number for any BLH).
dave
Also, need to learn/understand the [T/S] driver specs and how they interact and WRT to the fact that Qes' [[Qes+ RS] = effective motor strength]] is the dominating spec of all box design until its Vas spec [compliance] becomes very large: Thiele Small parameters equations - How each one affects the others
GM
The abbreviated technical terms makes very difficult for me to understand...
Now I understood! ��
What I not understood yet is, how to know if the damping factor of an amp, is too high for the fostex fe208Ez, or is optimum?
"Originally Posted by Scottmoose View Post
This has been explained to you before as I recall. Damping factor is a unitless (and in my view rather useless) measurement which is taken as the load impedance [Zl] in ohms divided by the output impedance of the source [Zs] in ohms.
In other words, look at the impedance plot of your loudspeaker and pick its lowest point. That is Zl. Divide that by the output impedance of your amplifier and you get a number for the unitless Damping Factor [DF].
Say your loudspeaker's lowest impedance is 3.6ohms, and your amplifier has an output impedance of 2.4ohms. Therefore since DF = Zl/Zs
DF = 3.6 / 2.4
DF = 1.5"
So far this was the better explanation that I understood, about how a damping factor is calculated.
Now I understood why damping factor is a unitless measurement, and how to calculate..
but when reading again, a doubts appeared, let's say that I will to this calculation that Scott taught me.
I understood how to look at the speaker's impedance graphic, and find the lowest point, in order to know the ZI.
Now: "Divide that by the output impedance of your amplifier"
I noticed that mostly manufacturers describe the output impedance like this:
Leben Hi-Fi Stereo Company
OUTPUT IMPEDANCE 4/6/8 Ohms (Selectable)
But this is not output impedance, they are just the speakers terminal, doesn't? not the actual output impedance about the amp...
but when reading again, a doubts appeared, let's say that I will to this calculation that Scott taught me.
I understood how to look at the speaker's impedance graphic, and find the lowest point, in order to know the ZI.
Now: "Divide that by the output impedance of your amplifier"
I noticed that mostly manufacturers describe the output impedance like this:
Leben Hi-Fi Stereo Company
OUTPUT IMPEDANCE 4/6/8 Ohms (Selectable)
But this is not output impedance, they are just the speakers terminal, doesn't? not the actual output impedance about the amp...
Depends, they are claiming the amp has a DF = 1, but short of measuring it, no way to know for sure.
GM
GM
The abbreviated technical terms makes very difficult for me to understand...
Then you have a lot to learn about the electrical, mechanical, acoustical theories behind them that are normally taught at a technical college.
GM
Greets!
You're welcome!
Technically, damping factor [DF] is the specified load impedance (speaker system) divided by the amplifier's output impedance, so dividing 8 ohms [speaker tap]/3.8 [DF] = 2.1 ohms output impedance [Rs].
Qts' = Qts + any added series resistance [Rs]: HiFi Loudspeaker Design
Hornresp automatically does this, so using a classic reflex alignment for comparison; inputting 0.5 ohms for wiring and 2.1 ohms amp [Rs] = 2.6 ohms in the [Rg] field and with a so called matching impedance 8 + 0.5 = 8.5 ohms.
Big difference and will be more extreme loaded in a BLH, so figure you'll need a relatively large series resistor, which won't sound the same as a matching impedance amp, i.e. DF = 1.
GM
Okay, let me try to understand this:
The method that Scott taught me, is the way to know the measurement of an amp's damping factor.
Now this method, is to know the same thing, but on the measurement of output impedance (aka as damping factor too), is just the another measurement language for the same thing.
Correct?
This has been explained to you before as I recall. Damping factor is a unitless (and in my view rather useless) measurement which is taken as the load impedance [Zl] in ohms divided by the output impedance of the source [Zs] in ohms.
In other words, look at the impedance plot of your loudspeaker and pick its lowest point. That is Zl. Divide that by the output impedance of your amplifier and you get a number for the unitless Damping Factor [DF].
Say your loudspeaker's lowest impedance is 3.6ohms, and your amplifier has an output impedance of 2.4ohms. Therefore since DF = Zl/Zs
DF = 3.6 / 2.4
DF = 1.5
By the way... the amp's output impedance, that I have to use on this formula, it's not this? right?
"OUTPUT IMPEDANCE 4/6/8 Ohms (Selectable)"
As is described on the Leben integrated CS-300X for example...
Leben Hi-Fi Stereo Company
Even they describing as output impedance, this are just the speaker's terminals.... not the real output impedance of the amp, correct?
In order to know the real amp's output impedance, there's another calculation to be done, that is what GM is trying to teach me...
Correct?
Thanks!
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