QUASI Amplifier for Beginners - Page 11

joka22 · 1st July 2010, 06:05 PM

here you go

krachkiste · 4th July 2010, 09:43 AM

(65v)²/2 / 4r = 528.125w

djk · 4th July 2010, 11:06 AM

So you have a regulated supply, and an amplifier circuit that can swing rail-to-rail with zero loss?

krachkiste · 4th July 2010, 12:02 PM

my point is, what do you assume to get from a +-65V supply to the 2xxW at 4Ohm load.

This seems a little too low to me even when you also take output swing and rail "breakdown" into account, and I want to understand how you got to this figure.

apexaudio · 4th July 2010, 01:11 PM

Quote:

Originally Posted by apexaudio

If you can have PSU without voltage drop with full output power, you can get 120Vpp or 42vRMS output voltage with +/-65V DC rail voltage. That will be 225W/8R or 450W/4R with 1% THD, or 300W/4R with 0,1% THD like CROWN DC300 with 1,5kW transformer. Power is not important, this amplifier give great chance for begginers to made functional amplifier.
Regards

post #59

krachkiste · 4th July 2010, 01:26 PM

ah, thanks apex.

joka22 · 5th July 2010, 03:20 PM

so anyone interested in swapping?

rhodrich · 31st July 2010, 03:10 AM

sir apex,

do you have a design of simple amplifier that can be used to drive a sub on 4 ohms load at 2000 watts and dont have a step driver?

djk · 09:48 AM

Without a step it would require 40 of MJ21196 outputs, two of the basic design (bridged, 20 per half amplifier) and running on about ±95V. Doubling up on the drivers will also be needed, and most of the smaller transistors (including the drivers) will need to be changed to higher voltage types.

I would consider a stepped supply, six pair of MJ21195/96 on the lower rails would be adequate for 2KW/4R.

rhodrich · 31st July 2010, 01:28 PM

Quote:

Originally Posted by djk

Without a step it would require 40 of MJ21196 outputs, two of the basic design (bridged, 20 per half amplifier) and running on about ±95V. Doubling up on the drivers will also be needed, and most of the smaller transistors (including the drivers) will need to be changed to higher voltage types.

I would consider a stepped supply, six pair of MJ21195/96 on the lower rails would be adequate for 2KW/4R.

djk

135vdc supply do you have a schematic for 2kw at 4 ohms

4th July 2010, 11:06 AM	#103
djk diyAudio Member Join Date: Feb 2001 Location: USA	So you have a regulated supply, and an amplifier circuit that can swing rail-to-rail with zero loss? __________________ Candidates for the Darwin Award should not read this author.

31st July 2010, 09:42 AM	#109
djk diyAudio Member Join Date: Feb 2001 Location: USA	Without a step it would require 40 of MJ21196 outputs, two of the basic design (bridged, 20 per half amplifier) and running on about ±95V. Doubling up on the drivers will also be needed, and most of the smaller transistors (including the drivers) will need to be changed to higher voltage types. I would consider a stepped supply, six pair of MJ21195/96 on the lower rails would be adequate for 2KW/4R. __________________ Candidates for the Darwin Award should not read this author. Last edited by djk; 31st July 2010 at 09:48 AM.

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4th July 2010, 09:43 AM	#102
krachkiste diyAudio Member Join Date: May 2009	(65v)²/2 / 4r = 528.125w

4th July 2010, 12:02 PM	#104
krachkiste diyAudio Member Join Date: May 2009	my point is, what do you assume to get from a +-65V supply to the 2xxW at 4Ohm load. This seems a little too low to me even when you also take output swing and rail "breakdown" into account, and I want to understand how you got to this figure.

4th July 2010, 01:26 PM	#106
krachkiste diyAudio Member Join Date: May 2009	ah, thanks apex.

5th July 2010, 03:20 PM	#107
joka22 diyAudio Member Join Date: Jun 2007	so anyone interested in swapping?

31st July 2010, 03:10 AM	#108
rhodrich diyAudio Member Join Date: Jul 2008	sir apex, do you have a design of simple amplifier that can be used to drive a sub on 4 ohms load at 2000 watts and dont have a step driver?