I have this Dayton Transducer and I wanted to know which amp specification will give me the best result for driving it? (Meaning no distortion at maximum volume)
what I should calculate using ohm law?
what will be the difference if using 12V amplifier vs 24V amplifier? what I should consider checking if my transducer is 25W 8ohm vs 25W 4ohm?
Thanks for any clarification
what I should calculate using ohm law?
what will be the difference if using 12V amplifier vs 24V amplifier? what I should consider checking if my transducer is 25W 8ohm vs 25W 4ohm?
Thanks for any clarification
Powering a specific amp with 24 V rather than 12 V will allow more undistorted power to be delivered into your 8 ohm exciter.
I believe you have had previous success with a TPA3116 12V/24V amp board so why not use another one?
https://www.amazon.com/Diymore-TPA3...18-8346-c1e0d34e098f&pd_rd_i=B01M0FO1JZ&psc=1
Let's say that to get 30 W out of this amp you need to put 120 W in to allow for inefficiencies.
Then power supply current = power / voltage = 120 W / 24 V = 5 A. This figure represents the minimum current the power supply must be capable of delivering to the amp.
The amplifier above will deliver less power into 8 ohm than into 4 ohm. The specs of the chip say 30 W into 8 ohm at 24 V, so make sure your power supply has a minimum current rating of 5 A.
Hope that helps!
Why it will allow more undistorted power to be delivered into an 8 ohm exciter?
why is that?
how you arrive for 5A needed? what is the calculation you made?
I showed the calculation - the two halves of my post interrelate. Besides, it's always better that the power supply has a large current rating. It doesn't mean that this large current is supplied continuously - the actual amount drawn by the amp depends on the setting of the volume control.
A large amount of the energy supplied to an amplifier is converted into heat in the amplifier so is not available at the output - although Class D amps are more efficient than other classes in this respect.
Because power = voltage squared / resistance, the bigger the voltage the greater the power delivered to a given resistance/impedance.
is this a rule of thumb that if I want to power a speaker that is x Watt I should use a amplifier that can deliver ~4 times more that x Watts ?
I was talking about ensuring sufficient current capability of a power supply, not about powering speakers.
During my 70s mobile disco days, I always ensured that the RMS power rating of the speaker system was twice the RMS power rating of the amplifer.
Suffice it to say that I never blew a speaker over a decade or so of high energy discothequeing!
During my 70s mobile disco days, I always ensured that the RMS power rating of the speaker system was twice the RMS power rating of the amplifer.
Suffice it to say that I never blew a speaker over a decade or so of high energy discothequeing!