What will happen when using 16 ohm load on a 8 ohm designed crossover

[fabricadetabaco]

I know the basic theory that the crossover points for a first order xo will go 2x up or down depending on whether its a HPF or LPF when using 16 ohm load instead of 8.
But some context here.

I have a pre-build PA crossover 1,6kHz/8 ohm which is a third order HPF and second order LPF.
I have no idea how it will react if I
A) use two serial connected 8 ohm woofers (sum 16 ohm) on LPF side,
and B) add a 8 ohm resistor to the tweeter to attenuate it on the HPF side.

I understand I can use a L-PAD to maintain the HF ohm but my goal is actually to see if I can somehow increase the HPF XO point and maybe also investigate if the slope can be tamed in way not to have such a brutal Q around the xo point.

Unfortunately I cannot install any sim programs...

 

[MarcelvdG]

For the low-pass, the quality factor will probably double while f_n stays as is, in other words, you get some peaking.

 

[fabricadetabaco]

I would actually expect the oposite; a less step crossover around +/- 1 octave.

 

[steveu]

FYI, a simulation for 8 and 16 Ohms. Note that unloading (16 Ohms) the XO causes about 6dB peaking. But note that real speakers are not resistors and the impedance at 1600Hz is not likely anywhere near 8 or 16 Ohms.

 

[fabricadetabaco]

That was not expected thanks.
So as drivers increase impedance with frequency there is a big chance I’ll get the same peaks or worse using nominal 8 ohm drivers as well then. Which explains my problem entirely I do have ugly peaks around the crossover point. I was hoping to tame it by going to 16 ohm but the opposite seems to be the case. So what if I parallel the LF drivers then. And use a parallel resistor on the HF side?

 

[AllenB]

Can you use EQ to reduce the crossover region?

 

[fabricadetabaco]

Not at this point but eventually yes. Which is why I won’t bother trying to assemble a new passive crossover.