# what value would this be?

#### cowanrg

##### Member
according to my attached picture, what would be the resistance across the positive and negative leads? (assuming im trying to make a dummy load for bench testing my amp). the resistors are 50W, 36ohm dale resistors. im really bad with kirchkoff's law, its been like 6 years.

#### Attachments

• resist.jpg
13.2 KB · Views: 112

21.333 ohms

Later
Bruce

#### Sparhawk

##### Member
In the text you mention 36 ohm, and in the diagram you say 32. Assuming 32 is the correct number, the total is 21.3 ohms as Bruce said. If 36 is the correct number, the total is 24 ohms.

If 32 is the correct value, 4 in parallel will give you 8 ohms, 8 will give you 4 ohms.

#### cowanrg

##### Member
oh, they are 36. so i guess its not possible to get an 8 ohm load from that then... sux.

#### Sparhawk

##### Member
5 of them in parallel will give you 7.2 ohms. Close enough to 8, maybe? #### BC108man

##### Member
how many do you have?

Nine(!) in parallel would be 4 ohms.
Do that twice, and put the 2 groups in series for 8 ohms.
This is assuming you've got an unending supply of the things!
Still, at least power dissipation per resistor won't be a problem...

Cheers, BC 