Yep, but Vp would be Vpp/2 and so 30V.W= ( (Vp/sqrt(2)) * (Vp/sqrt(2)) )/ R
which is the RMS value also.excuse me guys, but Vpeak/sqrt(2) is the effective value
For a sine wave, power is peak-to-peak squared divided by eight times resistance (that is, peak squared divided by twice resistance)
60 volts sine peak to peak into 8 ohms is P=56.25Watts.So like 60 volts sine peak to peak into 8 ohms is ____ watts RMS? And 60 volts square peak to peak into 8 ohms is ___ watts?
I mention this not to be contentious but to keep the original poster from getting confused
lgreen said:.....As for RMS, are not amplifiers rated to deliver so many watts per channel RMS???...