What is the difference between the resonant frequency and the (lowest) -3DB frequency

The level at the resonance is not always -3dB because the properties of the resonance can vary. This is referred to as its damping level or its Q factor. A simple inductor/resistor filter gives -3dB and that's the half power point.. but a 2nd order filter can have different amounts of damping. (The speaker/box resonance is second order)
 
Typical sealed alignment is a 2nd order filter = 6 dB/octave roll-off and since octave spreads are exponential (1/f), - 3dB is Fl = 38/2^0.5 = 26.87 Hz

Typical BR is 4th order = 12 dB/octave, so -3 dB = 38/2^0.25 = 31.95 Hz

As Allen noted though, this is 'textbook', i.e. at a typical default alignment (box/vent) damping.

Octaves math:

Fh = Fl*2^n

Fl = Fh/2^n

n = ln[Fh/Fl]/ln[2]

where:

Fh = upper frequency
Fl = lower frequency, or the XO point in this case
n = octave spread
ln[2] = 0.6931
 
I dont get it. Why is the resonant frequency 38Hz and the -3DB frequency 27Hz ? What is the difference and how is the -3DB Frequency calculated ?
Well that would depend on what is going on at resonance. The frequency response at resonance can take on a variety of shapes. see the plot at this link for example:
Fig2a.jpg

The above is model of the response for a subwoofer or woofer. In the plot, the frequency, f, has been normalized by the resonance frequency, fo. There is something called the "quality factor" (abbreviated as "Q" or Q-factor) that denotes how "peaky" the resonance is. The higher the number the higher the peak is above the "passband" level before the response falls off.

Looking at the graph you can observe that for a given resonance frequency the F3 frequency can be above, the same as, or below the resonance frequency depending on the Q factor. The plot shows the frequency responses for a variety of Q values, with key of values at the bottom.

When the passband is as flat as possible before turning down into the stopband, the Q factor is 0.707 and F3=Q. When Q<0.707, F3>fo and when Q>0.707 F3<fo.
 
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Typical sealed alignment is a 2nd-order filter = 6 dB/octave roll-off and since octave spreads are exponential (1/f), - 3dB is Fl = 38/2^0.5 = 26.87 Hz
Doesn't a 1st-order filter have a 6 dB/octave roll-off rate, while a 2nd-order filter has a 12 dB/octave roll-off rate? Of course, the slope in the region of the -3dB cut-off frequency is less than that.
Typical BR is 4th order = 12 dB/octave, so -3 dB = 38/2^0.25 = 31.95 Hz
A 4th-order filter has a 24 dB/octave roll-off rate.
 
View attachment 1049332
When the passband is as flat as possible before turning down into the stopband, the Q factor is 0.707 and F3=Q. When Q<0.707, F3>fo and when Q>0.707 F3<fo.
Referring to the underlined text, when the passband is as flat as possible before turning down into the stopband, the Q factor is 0.707 the –3dB point in the response is located at f/fo = 1 when using the above graph.
 
Typical sealed alignment is a 2nd order filter = 6 dB/octave roll-off and since octave spreads are exponential (1/f), - 3dB is Fl = 38/2^0.5 = 26.87 Hz

Typical BR is 4th order = 12 dB/octave, so -3 dB = 38/2^0.25 = 31.95 Hz
That's not quite right. You have the orders correct - sealed/closed box is second order and vented/ported is 4th order. But the ultimate rolloff in each case is 6dB per "order", so 2nd order = 2*6 = 12dB/octave and likewise 4th order is 24 dB/octave.
 
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Sheesh! I know this stuff inside out, but when I saw this combined with all the other similar/same stupid mistakes I've been making lately, time for me to step back and devote the time to dealing with my 'distractions'.
 
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