Ahh, the problems of typing without having the cct in front of you.
Nelson, the regulator seem to be hooked up slightly differently in Zv3 than in Zv4 but if i understand correctlythen what you're saying is...
Lose Q5 and all the zeners and associated cctry,
Change R0 and R1 back to the 0.33R of version 3.
The only thing i'm unclear on is the link thru c11/r19 down to the bottom of R0 and R1.
What does this do and can it be done away with? It wasn't on zv3.
As always, you're assistance to the diyers out there is very much appreciated
drew
Nelson, the regulator seem to be hooked up slightly differently in Zv3 than in Zv4 but if i understand correctlythen what you're saying is...
Lose Q5 and all the zeners and associated cctry,
Change R0 and R1 back to the 0.33R of version 3.
The only thing i'm unclear on is the link thru c11/r19 down to the bottom of R0 and R1.
What does this do and can it be done away with? It wasn't on zv3.
As always, you're assistance to the diyers out there is very much appreciated
drew
I know a man is teasing me.
He knows my figure is 2x1.5x14/2 = about 20.
I know his figure is 1.4x1.5x14/2 = about 14.
I know he loves this...
He doesn't know I love this¡¦
🙂
He knows my figure is 2x1.5x14/2 = about 20.
I know his figure is 1.4x1.5x14/2 = about 14.
I know he loves this...
He doesn't know I love this¡¦
🙂
Certainly our Icons are clear enough.
It's always worth running this down from the beginning.
Watts = Volts Squared / Resistance
If the peak swing is 10 volts, then V squared (V^2) = 100
If the resistance (or impedance) is 8 ohms, then the answer
is 12.5 watts
This applies to instantaneous wattage as well as rms.
If you have 12.5 watts rms, by definition you have 25 watts
peak, this being the nature of the sine wave.
If you have 12.5 watts rms, then you have 10 volts rms,
and the square root of 2 (1.41) times that for a peak.
14.1 volts peak is 10 volts rms is 25 watts peak, and
12.5 watts rms.
(I don't mean to abuse what might be obvious, but some
newbies might read this post.)
So if you have something like 34 volts on your supply,
you will have some losses due to the inability of the circuit
and the supply to make 100% use of it. I figure at least
3 volts loss on the + end, and 2 volts loss on the - end,
so we're looking at 29 volts. Like any chef, I figure another
volt lost to miscellaneous, and we have 28 volts.
Split this in half and we get +/- 14 volts.
This is 200/8 = 25 watts peak, 12.5 watts rms into 8 ohms.
If I have misunderstood you, then
It's always worth running this down from the beginning.
Watts = Volts Squared / Resistance
If the peak swing is 10 volts, then V squared (V^2) = 100
If the resistance (or impedance) is 8 ohms, then the answer
is 12.5 watts
This applies to instantaneous wattage as well as rms.
If you have 12.5 watts rms, by definition you have 25 watts
peak, this being the nature of the sine wave.
If you have 12.5 watts rms, then you have 10 volts rms,
and the square root of 2 (1.41) times that for a peak.
14.1 volts peak is 10 volts rms is 25 watts peak, and
12.5 watts rms.
(I don't mean to abuse what might be obvious, but some
newbies might read this post.)
So if you have something like 34 volts on your supply,
you will have some losses due to the inability of the circuit
and the supply to make 100% use of it. I figure at least
3 volts loss on the + end, and 2 volts loss on the - end,
so we're looking at 29 volts. Like any chef, I figure another
volt lost to miscellaneous, and we have 28 volts.
Split this in half and we get +/- 14 volts.
This is 200/8 = 25 watts peak, 12.5 watts rms into 8 ohms.
If I have misunderstood you, then
- Status
- Not open for further replies.