Hello all,
is it possible to connect a volume potmeter in a balanced line? My guitar is equipped with a low impedance p.u. and is connected to an audio mixer (XLR, low Z, hot, return and shield). My goal is to use a volume foot pedal with this guitar but all the pedals I know of are high Z unbalanced. Maybe someone can help me out on this one? Thanks a lot, Bouatila!
is it possible to connect a volume potmeter in a balanced line? My guitar is equipped with a low impedance p.u. and is connected to an audio mixer (XLR, low Z, hot, return and shield). My goal is to use a volume foot pedal with this guitar but all the pedals I know of are high Z unbalanced. Maybe someone can help me out on this one? Thanks a lot, Bouatila!
You can use a stereo pot. They can be scavenged from old amplifiers but can also be found at Digikey I would believe.
Best Regards
Tom
Best Regards
Tom
just insert the pot (connected as a variable resistor) between hot and cold. No connection to signal ground.
If the line resistor in the hot and in the cold is too low then the impedance seen by the source will fall drastically as the attenuation is increased.
Depending on the impedances of the source and of the receiver, you will have to determine the line resistors and pot value to get the attenuation rates you require.
If the line resistor in the hot and in the cold is too low then the impedance seen by the source will fall drastically as the attenuation is increased.
Depending on the impedances of the source and of the receiver, you will have to determine the line resistors and pot value to get the attenuation rates you require.
MisterStarshine said:You can use a stereo pot. They can be scavenged from old amplifiers but can also be found at Digikey I would believe. Best Regards Tom
... and that's what I did and it works like a charm! Thank you for sharing this splendid idea. I used a 10k log stereo pot and first made a testing configuration. Now that it works I plan to convert an Ernie Ball volumepedal. E.B. have a stereo low impedance pedal, but their 25k is way too much.
Ciao, Bouatila
<just insert the pot (connected as a variable resistor) between hot and cold. No connection to signal ground.
If the line resistor in the hot and in the cold is too low then the impedance seen by the source will fall drastically as the attenuation is increased.
Depending on the impedances of the source and of the receiver, you will have to determine the line resistors and pot value to get the attenuation rates you require. regards Andrew T.>
Thank you for thinking along with me. I went for the stereo pot option: it works splendidly. Ciao, Bouatila
If the line resistor in the hot and in the cold is too low then the impedance seen by the source will fall drastically as the attenuation is increased.
Depending on the impedances of the source and of the receiver, you will have to determine the line resistors and pot value to get the attenuation rates you require. regards Andrew T.>
Thank you for thinking along with me. I went for the stereo pot option: it works splendidly. Ciao, Bouatila
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