Hello, I'd like to know the reason Western Electric used a voltage divider (VD)in the driver tube (310) in G2 instead of a more standard dropping resistor. The image shows the SP 91 version with divider in R8/R7 (arrow) and standard setup in generic pentode (right).
Although the voltage divider is easy to understand there is an aditional current to ground. How do you manage to calculate Ig2 current regarding the VD. Just trying to understand the circuit well.
Best regards
Roberto luis, Argentina
Although the voltage divider is easy to understand there is an aditional current to ground. How do you manage to calculate Ig2 current regarding the VD. Just trying to understand the circuit well.
Best regards
Roberto luis, Argentina
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