Hi all,
i have very por basics so please solve the question and let me know how you did it.
The circuit is attached with the thread. you need to find ?
Vasu
i have very por basics so please solve the question and let me know how you did it.
The circuit is attached with the thread. you need to find ?
Vasu
It would be 2.7v. A regular forward biased diode has a 0.7v drop. Schottkys can have as low as 0.2v drop depending on design.
thanx...
it never stuck me...
i know of 0.7V drop.
I am trying to build a and circuit using diode, and the output would be lower of the two inputs always.
so was working on drops across the diodes.
thankyou for prompt reply
vasu
it never stuck me...
i know of 0.7V drop.
I am trying to build a and circuit using diode, and the output would be lower of the two inputs always.
so was working on drops across the diodes.
thankyou for prompt reply
vasu
when 5V is at one end of the resistor and 2.7V is at the other end of the resistor you can calculate the current through the resistor and the diode.
[5-2.7] / 10k = 0.00023 = 230uA.
[5-2.7] / 10k = 0.00023 = 230uA.
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