Understanding Oscilloscope voltage rating

G'day Guys,

I am trying to make sure I correctly understand the voltage ratings of my oscilloscope before I blow something up.
My scope is an Owon SDS210S
https://owon.com.hk/products_sds200_series_digital_oscilloscope

The voltage rating of the scope is 400V
scope.png


If I understand this correctly:
The voltage must not exceed 400v total including any and all AC + DC components.

Then there is the probes:
The OW3100 probes that come with it state:
"1x ≤ 200Vpk 10x ≤600Vpk"

If I understand this correctly:
Under 200Vpk I can use the probe in 1x mode.
Between 200Vpk and 600Vpk I can use 10X mode.

I assume Vpk here refers to the total voltage of any and all ac + dc components.

So assuming I have all of the above correct:
As long as I keep my probes in 10x attenuation I can safely probe a tube preamp with a 265Vdc B+ and its power supply with its maximum raw B+ of 330ish Vdc.

Have I missed anything?
 
...as well as more accuracy, more sensitivity and less noise.

I think you have to be careful with DC voltages above 400 V. A passive 10:1 probe is essentially a 9 Mohm series resistor with a small capacitor across it and a cable. When the oscilloscope input is AC coupled, any DC voltage at the probe input occurs across the oscilloscope's input AC coupling capacitor unattenuated. Fortunately your supply voltages are below 400 V.
 
The usual interpretation is that under no circumstances should the instantaneous voltage exceed plus or minus xxx volts. There are usually some frequency factors as well, that they often don't talk about. You can use an X1 probe, usually AC coupled, when looking at power supply ripple and other low impedance signals where you need maximum sensitivity. The bandwidth will still be plenty for most audio need, up in the MHz with no problem. To get the rated BW of the scope you'll need either an X10 probe or a 50 ohm terminator, if the source can drive it.