Vs= ±70V, Load=4Ω
circuit
Q: Why the power curve was parabolic?
i.e. low and high output voltage has low dissipation.
An externally hosted image should be here but it was not working when we last tested it.
circuit
An externally hosted image should be here but it was not working when we last tested it.
Q: Why the power curve was parabolic?
i.e. low and high output voltage has low dissipation.
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P=Volts X Current
all current no volts, no power
all volts no current, no power
When the transistor is supplying lots of current with lots of volts still across it, dissipation is high.
all current no volts, no power
all volts no current, no power
When the transistor is supplying lots of current with lots of volts still across it, dissipation is high.
@Ian : I've change the image now. thanks.
@Andrew :
the LTspice formula to express Transistor Q1 dissipatioan is as follow:
V(Vcc,out)*Ic(Q1) + V(Vin,out)*Ib(Q1)
what is V(Vcc,out)? is that mean V(Vsupply-Vout)?
if I want to calculate power dissipation at output=10V,
then it would be :
V(70-10)*2.5A = 150W + V(Vin,out)*Ib(Q1) [which is low enough]
that should be correct, right?
@Andrew :
the LTspice formula to express Transistor Q1 dissipatioan is as follow:
V(Vcc,out)*Ic(Q1) + V(Vin,out)*Ib(Q1)
what is V(Vcc,out)? is that mean V(Vsupply-Vout)?
if I want to calculate power dissipation at output=10V,
then it would be :
V(70-10)*2.5A = 150W + V(Vin,out)*Ib(Q1) [which is low enough]
that should be correct, right?
That's right. That's also why an amp with 70v rails designed for a 4 ohm load will have many parallel output devices.
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This appears to be a DC calculation. Fine for a servo mechanism, but for an audio amplifier you need to do an AC calculation and average over a complete cycle. To do this properly involves some simple calculus.kroto said:if I want to calculate power dissipation at output=10V,
then it would be :
V(70-10)*2.5A = 150W + V(Vin,out)*Ib(Q1) [which is low enough]
Now throw in driving a reactive load like a speaker where the voltage is out of phase with the current. There will be situations where most of the voltage is across the transistor and most of the current flows at the same time.
Once the instantaneous die temperature gets to critical it's sayonara! And for BJT's there is secondary breakdown.......🙄

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