Hi,
I'm going to assemble a stereo class D amp based on the ucd400 modules from Hypex. In the mean time I'm trying to design a good phono pre amp able to feed the ucd400... but I'm a beginner so I still have few doubts 😕
Looking at the datasheet of the ucd400 I can see I have a 26dB voltage gain and max Vin = +/-12V, but I have no recommended Vin to get the most from the final amp. Now, I'd like to understand the Vpp I need to provide through my preamp so that I can really reach 400W@4Ohm.
Considering that 400W@4Ohm means a current of 10A, I assume the Vout of the Hypex module should be close to 40Vpp. To have 40Vpp at the output of the ucd400 I need at least 2Vpp as input (ucd400 gain = 26dB).
Is that correct?
In this can I need a preamp able to provide at least 2Vpp as output.
Based on your experience, do you think it's better to feed the Hypex module with an higher signal? let's say 5Vpp?
Thanks
I'm going to assemble a stereo class D amp based on the ucd400 modules from Hypex. In the mean time I'm trying to design a good phono pre amp able to feed the ucd400... but I'm a beginner so I still have few doubts 😕
Looking at the datasheet of the ucd400 I can see I have a 26dB voltage gain and max Vin = +/-12V, but I have no recommended Vin to get the most from the final amp. Now, I'd like to understand the Vpp I need to provide through my preamp so that I can really reach 400W@4Ohm.
Considering that 400W@4Ohm means a current of 10A, I assume the Vout of the Hypex module should be close to 40Vpp. To have 40Vpp at the output of the ucd400 I need at least 2Vpp as input (ucd400 gain = 26dB).
Is that correct?
In this can I need a preamp able to provide at least 2Vpp as output.
Based on your experience, do you think it's better to feed the Hypex module with an higher signal? let's say 5Vpp?
Thanks
Trying to answer my question.
In order to have 400W@4Ohm from ucd400 module, the Hypex monoblock must be able to provide a current of Iout = 10A and a voltage of Vout = 40V.
Considering the 26dB of voltage gain, to have Vout = 40V I need a Vin = 2V.
Now I assume we are talking about Root-Mean-Square Voltage, so Vin = 2V = Vrms.
That means Vpk = Vrms * Sqrt(2) = 2* 1.41 = 2.83V
That means Vpk-pk = 2 * Vpk = 5.66V
In other words if I want to have 400W@4Ohm (or 200W@8Ohm) from the ucd400 I need to provide Vpk-pk = 5.66V as input.
Does it sounds good?
In order to have 400W@4Ohm from ucd400 module, the Hypex monoblock must be able to provide a current of Iout = 10A and a voltage of Vout = 40V.
Considering the 26dB of voltage gain, to have Vout = 40V I need a Vin = 2V.
Now I assume we are talking about Root-Mean-Square Voltage, so Vin = 2V = Vrms.
That means Vpk = Vrms * Sqrt(2) = 2* 1.41 = 2.83V
That means Vpk-pk = 2 * Vpk = 5.66V
In other words if I want to have 400W@4Ohm (or 200W@8Ohm) from the ucd400 I need to provide Vpk-pk = 5.66V as input.
Does it sounds good?
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