TPA3116 on 1 ohm load

Not too weird
Id expect the power supply to shut down.
1 ohm is a ton of current.
For a single driver not much benefit.
Power supply is getting hammered.
Switch mode can do current but not
to great at it

Guess the 70's add copy lives on.
Low impedance doesnt give " more power"
it uses more power.
Numbers look good in the add though
 
IF TI suggests 3.2 ohm minimum load for a single 3116 and 1.6 for two in parallel (just read the datasheet), Logic/Math says you need three in parallel for 1 ohm.

Can use just two?
Yes, you can.
You can also drive with the handbrake engaged (I have a couple times).
Simply "not good Engineering"
 
Is it this driver?

No, 4 vintage 4 ohm AD8066 philips woofers which are setup in a 1:3 master-slave config with the master being servo controlled .

05FEB2024.jpg


The AD8066 master driver equipped with a StarBass accelerometer :

STARBASS.8066.2023.1.jpg

Not too weird
Id expect the power supply to shut down.
1 ohm is a ton of current.
For a single driver not much benefit.
Power supply is getting hammered.
Switch mode can do current but not
to great at it

Guess the 70's add copy lives on.
Low impedance doesnt give " more power" it uses more power.
Numbers look good in the add though

I eventually choose to go with 4 separate 3116 pbtl amps to drive each woofer individually:

02AUG2024.jpg


The discussion appears to assume a perfect power supply. With such a low impedance load, I wonder if the power supply is limiting the output current and protecting the amplifier?
In party mode the 4BMH6D module consumes upto 26A @ 24V which is equal to what it would take on a 1 ohm load.
 
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In party mode the 4BMH6D module consumes upto 26A @ 24V which is equal to what it would take on a 1 ohm load.
Fair point. But thinking broadly, there are three resistances in series here. There is the internal resistance of the power source, the series resistance of the amplifier and the one ohm speaker. So if at maximum output, the combined resistance of the power source and the amplifier is (for the sake of argument) a mere one ohm, then half the power is being dissipated there instead of in the loudspeaker. Wouldn't it work better to use one coil of the speaker and present a 2 ohm load?
 
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Fair point. But thinking broadly, there are three resistances in series here. There is the internal resistance of the power source, the series resistance of the amplifier and the one ohm speaker. So if at maximum output, the combined resistance of the power source and the amplifier is (for the sake of argument) a mere one ohm, then half the power is being dissipated there instead of in the loudspeaker. Wouldn't it work better to use one coil of the speaker and present a 2 ohm load?
Not sure if I understand you correctly, the drivers used are 4 ohms single coil woofers ?