Tone arm replacement?

I bought a used turntable off ebay and when I got it there was damage to it. I got refunded almost all of my money with the offer to keep the table for $20.00 so I took the offer thinking I might find a different tone arm for it.

If there somewhere a person can pick up a tonearm at a reasonable price? It there a correct distance from the center of the platter it needs to be installed? I guess a site where I can find all the info I need?

It has a really nice direct drive platter but a cheap tonearm.
 
To see if a replacement/different arm can be fitted we need to know the make & model of the turntable .

It isn't a simple matter of bolting in a different arm -geometry comes into it as well as other engineering adjustments.

No use fixing an expensive arm to a deck costing $$$$ less .
 
Seemingly sold by Seers and your right it was a "reasonable " but cheap deck at the time .

Its got auto return so you have to make up your mind --is it worth going to the trouble of aligning and drilling holes on a non AR arm that you have to manually operate --no .

What you can do is buy a non working but good tone arm model and transfer it over otherwise I would just put it down to experience.


Sorry being so negative but if it was an expensive deck then it would be worth the effort but I have seen one in GWO selling for $80 .
 
An Audio Research DD-1979

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Looks like it would be easy enuff. You’d have to lose the semi-auto stuff 1st.

I’d suggest anything you can get fairly cheap.

Something pulled off another cheap TT. Even a quick & nasty diy uni-pivot.

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Nanook’s $2.19 tonearm.

dave
 

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in answer to your earlier question - the critical measurement for installing a tonearm is the distance from the mounting point of the arm (the axis on which it pivots) to the center of the platter spindle. there is no absolute standard (that I am aware of) and it varies according to the length of the tonearm.

as an example, my Rega tonearm has a mounting distance of 222mm.

for commercial tonearms this length should be established. for DIY I would expect that somewhere out there on the Internet is an equation that will allow you to compute it. unfortunately I don't have a reference.

good luck,

-bill