Get a grip fer xsake. You're just confusing the issue.
When referring to measurements of field amplitude it is usual to consider the ratio of the squares. This means that the dB has the same effective meaning whether referring to voltage or power.
2x power (10 log10(Po/Pi)) = 3dB
2x voltage (20 log10(Vo/Vi)) = 6dB
1.41x voltage = 2x power = 3dB
Look it up.
2x the voltage is 4x the power, as you say. ((V^2)/R).
That's why there's one formula for voltage and another for power.
Forgot to add... (typed in a rush and didn't have internet afterwards)
In audio, people are more interested in SPL because that is what we hear. So the effect of changing any quantity is often reflected as the resultant change in SPL. So doubling pressure and voltage results in +6dB SPL, while doubling power and SPL results in +3dB SPL.
In audio, people are more interested in SPL because that is what we hear. So the effect of changing any quantity is often reflected as the resultant change in SPL. So doubling pressure and voltage results in +6dB SPL, while doubling power and SPL results in +3dB SPL.
Ok, so it's indeed confirmed that doubling watts consists in +3db.
While doubling/halving input voltage results in a +6db spl?
So for instance, if my preamp outputs 0.9v, and my amp as a consequence outputs 40watts, if I change the preamp ouptut to 0.45v, the amp outputs 10w?
While doubling/halving input voltage results in a +6db spl?
So for instance, if my preamp outputs 0.9v, and my amp as a consequence outputs 40watts, if I change the preamp ouptut to 0.45v, the amp outputs 10w?
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