Removing balance control

This amps been sitting on a shelf for circa 5 years as it has a broken all in one balance/volume control. The amp is a Kenwood model 500.

How would I go about removing the balance control from this circuit? Is it a case of remove and it'll work as intended or would I need to replace with fixed resistors?

Thanks
balance control.png
 
I expect banlace pot to be a log - reverse log type, so when set at midpoint you he an attenuation of abot 10% of voltage, I think you can simply put a jumper from mode switch S6 to volume control at pin 3, remove actual wire from mode switch to balance control, and also from balance control to volume potentiometer.
 
I expect banlace pot to be a log - reverse log type, so when set at midpoint you he an attenuation of abot 10% of voltage, I think you can simply put a jumper from mode switch S6 to volume control at pin 3, remove actual wire from mode switch to balance control, and also from balance control to volume potentiometer.

Thanks for your reply, so connect the L/R signal from the mode switch which is pre out before the balance control to the next stage of this 6 gang volume control which seems to be something to do with loudness? Any resistors needed?
 
As drawn. Remove it, then on the top one connect pins 2 & 3, on the bottom one connect pins 1 & 2. Done.
Or even easier, connect those points and leave the control in, it will be ineffective now.
When set at mid point there is no attenuation, see schematic. These type of pots have half of the tracks zero ohms, other half has a resistance track.

Jan
 
As drawn. Remove it, then on the top one connect pins 2 & 3, on the bottom one connect pins 1 & 2. Done.
Or even easier, connect those points and leave the control in, it will be ineffective now.
When set at mid point there is no attenuation, see schematic. These type of pots have half of the tracks zero ohms, other half has a resistance track.

Jan

Thanks Jan,

Easy to understand this just how I like it. Output to input
 
As drawn. Remove it, then on the top one connect pins 2 & 3, on the bottom one connect pins 1 & 2. Done.
Or even easier, connect those points and leave the control in, it will be ineffective now.
When set at mid point there is no attenuation, see schematic. These type of pots have half of the tracks zero ohms, other half has a resistance track.

Jan
I am surprise with this one, if we leave the pot connected and somebody turns the knob then the signal may short to ground...
 
Correct.
WRT the upper pot:
You must lift connection1 of the pot after following above instructions. Or lift 2 & connect it to 3. Or both.

Depending what's wrong with the pot, a broken resistance may affect the circuit if left in. L-R imbalance for example.

If it is a PCB pot then track cutting will be required.

Post a photo.