I'm using Peter Daniel's IGC schematic, with the 10k input resistor and the 220k feedback resistor.
But when I use it with my CD player (Marantz CD62), I don't even turn the volume pot more than 5%. 10% is real loud. (I've got 92dB/w/m speakers)
Could I simply lower the gain by increasing the input resistance's value?
I think that could be a good think, since it would also result to a higher input impedance.
Is there no problem in doing it?
But when I use it with my CD player (Marantz CD62), I don't even turn the volume pot more than 5%. 10% is real loud. (I've got 92dB/w/m speakers)
Could I simply lower the gain by increasing the input resistance's value?
I think that could be a good think, since it would also result to a higher input impedance.
Is there no problem in doing it?
It's a cheap Pihier stareo linear 50k pot.
Do you think a log would give me more sensitivity at low volumes?
In fact, I think it's true. But lowering the gain, and this way, rising the input impedance, looked nice to me.
But I can do both...
Do you think a log would give me more sensitivity at low volumes?
In fact, I think it's true. But lowering the gain, and this way, rising the input impedance, looked nice to me.
But I can do both...
I found that 50k log pot works much better than linear pot and gives better control over the usable range.
If you really insist on using linear pot in this application, the value should be higher (at least 100k) although I'm not sure it would give as good control range (as log pot).
I wouldn't lower the amp's gain, as supposedly, GC works better with higher gain.
If you really insist on using linear pot in this application, the value should be higher (at least 100k) although I'm not sure it would give as good control range (as log pot).
I wouldn't lower the amp's gain, as supposedly, GC works better with higher gain.
I'll change it.
I already wanted to do this, since the two channels aren't very well matched at low volume
I already wanted to do this, since the two channels aren't very well matched at low volume
Then yes, a logarithmic pot will solve the problem. That 10% of the linear pot will appear as the center position of the logarithmic one. Bad channel tracking you mentioned is the feature of all Piher pots which is a pity since these pots sound pretty dynamical (though not as clean and open as, say, ALPS, but the difference in cost is obvious). You should be really lucky to get the Piher with good channel tracking (or you should try at least a couple of them).Bricolo said:It's a cheap Pihier stareo linear 50k pot.
Pedja
Pedja said:
Then yes, a logarithmic pot will solve the problem. That 10% of the linear pot will appear as the center position of the logarithmic one. Bad channel tracking you mentioned is the feature of all Piher pots which is a pity since these pots sound pretty dynamical (though not as clean and open as, say, ALPS, but the difference in cost is obvious). You should be really lucky to get the Piher with good channel tracking (or you should try at least a couple of them).
Pedja
I've got a 100K log stereo Pihier with a good channel tracking.
But 100K could be too much for a gainclone.
I could also go the the local store with my dmm and ask to test a few 50K ones, the guy will certainly be ok
The 100k log will be fine considering the attenuating curve. However, the total gain with thus formed feedback will be likely too low - I liked better the sound of 50k pot with 220k/10k feedback network. The best for you - try both, especially because you already have one and you have a possibility to measure before you buy. Btw be careful (nothing special, a bit of care will be enough), Piher is fragile and might not be happy because of too many/long soldering and/or too hot soldering iron.
Pedja
Pedja
...or build the stepped attenuator described on my Gainclone FAQ page which is designed for the IGC.
Cost is about 15-20 euros depending on what type of resiistors you use.
Cost is about 15-20 euros depending on what type of resiistors you use.
Since 10K is plenty high enough already, a better solution is to reduce the value of the feedback resistor. The only reason to increase the value of the input resistor would be if the device driving it cannot handle that much of a load. Don't forget that resitors make noise (thermal resistance) which is higher for higher value resistors. Using lower value R's will reduce noise (hiss) in your amp.Could I simply lower the gain by increasing the input resistance's value?
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