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Phase splitter output discrepancy

What is the + 5.5V supply for?

Did you mean - 5.5V to run the input tubes CCS? . . . (minus 5.5V).

Check the voltage polarity to the CCS.
Check the CCS, if it is bad, the input tube that is connected to the input signal connector will have more plate signal, than the other input tube plate.
You said 50% difference.

Re-check the 100k feedback resistors; the input tube 10k plate load resistors, the output transformer primary (as the earlier post-ers said).

Is the primary connected properly?
The DCR from one primary plate lead to the B+ center tap, should be close to the DCR of the other primary plate lead to the same B+ center tap.

The +5.5V supply is for the CCS. And yes, it is PLUS 5.5V.
Primaries correctly connected. Same dcr on both phases.
 
What happens if you just swap the output tubes? Does the issue travel with the tubes? Could be grid current of one tube..
Could also be a leaking coupling C...
Also check your decoupling caps on the output tubes as well just in case...

I swapped all tubes in all possible ways. Replaced with new ones etc etc. No significant difference.

I measured the output tube grids, they both are around 0.001V.
I haven't taken out the coupling caps for further measurement, but they seem to do their job.
 
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What kind of current source are you using for the input tubes?

Schematic of the CCS circuit, please.

You have checked everything else; try checking the CCS.

Why does the current source need +5V.
Most current sources start with a Negative voltage at the bottom, then the top of the current source goes to the cathodes.
That way, with the cathodes at perhaps +3V for example, the current source has -5V to +3V across it (8V), plenty of voltage to meet the burden voltage of most current sources.

Check that both supplies are equal, either +5V and +5V; or -5V and -5V.
Then swap the current sources.
 
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The +5.5V supply is for the CCS. And yes, it is PLUS 5.5V.
Primaries correctly connected. Same dcr on both phases.
You have labelled the voltages on the rectified supply for the CCS as +5.5V and 0V, but it seems like that is not what they'd actually be, because of those 100ohm resistors that are tying the midpoint of the 6.3Vac heater supply to ground. Wouldn't the two recified supply outputs be at something like +2.25V and -2.25V? Maybe this is OK, but without seeing the schematic for the CCS it is difficult to tell.
 
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Here's the CCS. Be gentle, it was the first CCS I ever designed with trasistors. And without a negative rail.
I'm inclined to drop it, and install a negative supply and just use a really big resistor in the tail. I've got a 50V bias tap left on my PT.
IMG_0348.JPG
 
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Here's the CCS. Be gentle, it was the first CCS I ever designed with trasistors. And without a negative rail.
I'm inclined to drop it, and install a negative supply and just use a really big resistor in the tail. I've got a 50V bias tap left on my PT.
View attachment 1167508
it needs a negative supply, cause transistor may be underbiased, with some tubes it may work but in most cases the tube will only droping a couple of volts, then if the tubes are unmatched the available voltage for the ccs will be less, the red led bias at the transistor is 1.8V so the cathode available voltage will be less cause it would need to be higher than the base to conduct, when driving signal, it will become negative and abrupt cut or plain oscilate
 
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An issue with CCSs is called voltage overhead (among other names), meaning how little voltage can it have across itself and still be a CCS. The voltage at the "top" of your CCS is the DC common cathode voltage, at idle (no signal) plus and minus 1/2 of the input signal voltage to the amp, with signal. First thing is to measure that DCV. Then figure the signal voltage added to that. Let's pretend signal voltage at the input jack is 1.0 VRMS, so signal voltage at common cathodes is half of that: 0.707 VPeak positive and negative.

The CCS needs to operate properly down to DC common cathode voltage minus 0.707 Volts. Does yours do that? Let's assume that yours works well enough down to a voltage (at it's CCS output) of the voltage across a red LED plus a few tens of a Volt, with zero margin for error.

If one were to measure the DC common cathode voltage and the DCV across the red LED, one would resolve this issue. Or converting to a negative DCV supply, which would give plenty of headroom.

Don't know if this will solve your issue, but needs to be explored. And painless enough to do.

All good fortune,
Chris
 
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