Hi everyone .
I built a cardboard model because an image is essential to ask my question, otherwise it is difficult to explain using only words.
in the photograph you can see two identical speakers placed in a casing. for the moment let's establish that the box is closed and leave aside the type of loading.
we connect the two speakers to the same channel of the amplifier but to one of the two we apply the reversed polarity.
when one driver pushes forward the other pushes backwards and vice versa.
what happens inside the casing and on the cone of the two speakers?
I built a cardboard model because an image is essential to ask my question, otherwise it is difficult to explain using only words.
in the photograph you can see two identical speakers placed in a casing. for the moment let's establish that the box is closed and leave aside the type of loading.
we connect the two speakers to the same channel of the amplifier but to one of the two we apply the reversed polarity.
when one driver pushes forward the other pushes backwards and vice versa.
what happens inside the casing and on the cone of the two speakers?
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Inside the box I would say the pressure fluctuations are neutralized, outside a lot of cancellation and comb filtering. I'm sure you can sim but the speakers are right there so you should just measure.
Not much happens inside, as the volume stays close to constant.
"Noise" is not precise enough, I would call it sound cancellation.Noise cancellation
Notice Arivel did not "get it":
amplifier noise?
Not even necessary 😄You should get acquainted with vituixcad.
True.Not much happens inside, as the volume stays close to constant.
"Sound cancellation" explains it fine and describes the audible result.
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