Lets consider we have two amplifiers in push pull output config with a pair of transistors now in general the positive wave is being handled by one transistor and negative wave is being handled by another one so now the question is ...
when we bridge the amplifier then half wave will go to one amp and another half will go to the second amplifier. Now when the positive wave goes to one amplifier since its nature is positive and it receives only positive wave so does it mean that only one transistor will be used in each?
in the same way for the negative transistor does the negative transistor only works?
I just want to know so that I would be wasting alot of transistors in building bridge amplifier for high power application...
how does this actually work as if its still using all the transistors despite of the complimentary pair but this is being in doubt for quite some time please clarify my doubt...
when we bridge the amplifier then half wave will go to one amp and another half will go to the second amplifier. Now when the positive wave goes to one amplifier since its nature is positive and it receives only positive wave so does it mean that only one transistor will be used in each?
in the same way for the negative transistor does the negative transistor only works?
I just want to know so that I would be wasting alot of transistors in building bridge amplifier for high power application...
how does this actually work as if its still using all the transistors despite of the complimentary pair but this is being in doubt for quite some time please clarify my doubt...
I think this is the root of your misunderstanding. The same half wave goes to each amplifier, but for one amplifier that half wave is inverted. As one amp sees the signal going positive to negative, the other amp sees an identical signal going negative to positive. That doubles the voltage across the load.
oops my mistake ...yeah in that case it does the voltage gain but what about the current gain? does all the output transistors are being used?
Ohm's law... if voltage increases across the same load, current must also increase.
The transistor action is the same whether bridged or not, it is just the opposite transistor working in the two amps at any given time.
The transistor action is the same whether bridged or not, it is just the opposite transistor working in the two amps at any given time.
Trace the current from say the pos supply of one amp, through the upper transistor, into the load, out of the other side of the load, into the lower transistor of the 2nd amp, to the 2nd amp neg supply. Simple. Invert for other polarity signal.
jan
Bridging of a lot of devices can offer the cancelling of even harmonics and +6dB of odds. So may well lower overall distortion as long as the evens are generally lower than the odds and the amplifier can drive effectively half the impedance without substantial distortion increase.
Push-pull already cancels evens. You are unlikely to get much further cancellation by bridging.
Odds, like the signal itself, get their voltage doubled so as a fraction this is 0dB.
Odds, like the signal itself, get their voltage doubled so as a fraction this is 0dB.
Harmonics being multiples of a fundamental frequency it seems
not obvious that the second harmonic has , well , three times
higher frequency than said fundamental , prove is that "second
harmonic" is generaly used to qualify...the first harmonic that
has double the fundamental frequency...
not obvious that the second harmonic has , well , three times
higher frequency than said fundamental , prove is that "second
harmonic" is generaly used to qualify...the first harmonic that
has double the fundamental frequency...
The normal usage in electronics is that second-harmonic is caused by second-order distortion (and other even orders) and has a frequency of twice the fundamental. Musicians may differ.
Second harmonic = 2x fundamental frequency
First harmonic = 1x fundamental frequency = fundamental frequency
Harmonic - Wikipedia, the free encyclopedia
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