# Jung problems

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#### rhymeswthorange

I built a jung super regulator according to the schematic given at http://tangentsoft.net/elec/opamp-linreg.html . When I plug it in, the LED goes green for a second and then turns off. I also get about 9 volts higher at output than I am supposed to be getting (LED is off). I'm using a 890/1.13k combo for R1 and R2, respectively, to get a little above 12V output. What could be going wrong? Thanks!

#### aparatusonitus

Check all wireing, all diodes & el. caps orientation for start.

#### jan.didden

Paid Member
What's your input voltage? Are you sure about it? You say you expect 12V, but with R1=890, R2=1.13k, you design for Vout = 15.6V. You should have at least 18VDC at the input. Is that right?

If not, the opamp will increase its output voltage in an attempt to get to 15.6V, and the collector of Q2 rises until its Q-B junction starts to reverse conduct, and the voltage across R4 goes up until there is no more voltage (or even reverse voltage) across the LED, it goes off.

Jan Didden

#### rhymeswthorange

My input voltage is at least 20V off-load. I'm using a PCB mount Amveco toroidal transformer (two 7v windings in series) with a bridge rectifier. On load it should give a little higher than 18V.

Also, when you use the equation R8 = R9*(Vout-Vref) / Vref , and substitute 890 for R8, 1130 for R9, and 6.0 for Vref; you get 12.33V for Vout.

Thanks for the help, can you guys think of anythig else that could be wrong? Seems like the voltage isn't being regulated as the output is about the same as the input voltge.

#### jackinnj

rhymeswthorange said:

Also, when you use the equation R8 = R9*(Vout-Vref) / Vref , and substitute 890 for R8, 1130 for R9, and 6.0 for Vref; you get 12.33V for Vout.

The LM329DZ as VRef will yield 6.9V, not 6.0V --

While it isn't a problem here, Jung pointed out in the TAA 2000 issue -- that there are occasionally dud LM329's so make sure that it is actually working.

PS -- Jan wrote one of the original series (1995) articles.

#### rhymeswthorange

Yeah, I meant 6.9 (calculation yields 12.33 with 6.9). Alright, I'll check it out. Thanks!

#### rhymeswthorange

Could a failed opamp cause this? The one I ordered was a surface mount type (SOIC-8), and after some effort I eventually got single strands of wire from my stranded hookup wire soldered to each contact. I wonder if in the process of doing this, I damaged the amp. The soldering iron wasn't held to the leads for very long (didn't need to be), but how sensitive are these chips to heat? Could, say, a second of soldering undo the chip? I also wiped some excess flux away with some alcohol (and let it dry before it was fired up). Would a failed opamp cause this type of behavior?

P.S. I have yet to check the other suggestions - have to get home first

#### rhymeswthorange

Well, now i supplied the regulator with a 460 ohm load. The LED stays on, and the voltage aross the load is 18V. When I put a 250 ohm load on it, the voltage across is 15.2. Is this supposed to be happening?

... at least the lights are on...

#### rhymeswthorange

Anyone have any ideas?

#### jackinnj

what's the voltage on pin6 of the AD825?, did you use a 1n5235 zener diode or a 1n4148 from the opamp to the collector of Q3?

#### jan.didden

Paid Member
Yes, you really should measure the in/output of the opamp. Second guessing and groping around in the dark is VERY inefficient.

You're still off on Vout. Across the 890 ohms there is 6.9 V. Therefore, across the 1130 there is 1130/890 * 6.9 = 8.76 volts. Therefore, Vout = 15.66V. Since the opamp needs some volts to operate, and you also loose some in the series transistor, you need probably a minimum of 20VDC input under load. Please check.

Jan Didden

#### jackinnj

janneman said:
Yes, you really should measure the in/output of the opamp. Second guessing and groping around in the dark is VERY inefficient.

You're still off on Vout. Across the 890 ohms there is 6.9 V. Therefore, across the 1130 there is 1130/890 * 6.9 = 8.76 volts. Therefore, Vout = 15.66V. Since the opamp needs some volts to operate, and you also loose some in the series transistor, you need probably a minimum of 20VDC input under load. Please check.

Jan Didden

you also lose across the LM317 pre-regulator -- (the version which I built did not incorporate this.)

#### rhymeswthorange

As for the Vout, switch the two resistor values you're using and you'll get my 12.33V. Across the 1130 ohms there is 6.9 V. Therefore, across the 890 there is 890/1130 * 6.9 = 5.43 volts. Therefore, Vout = 12.33V.

I'm using a 1n5235 zener to the collector of Q2.

I'll measure voltages as soon as I get home.

Thanks again for all the help!

#### jan.didden

Paid Member
We may still talk about different things.
I'm not using R1, R2, you are.
In the Jung schematic where there are R1 and R2, I see a 1N4148 diode, not a zener. And in that diagram, Vout = 15,66, sorry.
How many volts is that zener?

What else is different?

Can you post a diagram of the one YOU buiilt? We may catch something that went unnoticed so far.

Jan Didden

#### rhymeswthorange

Pin 6 (output) has 13.5V (w/ respect to ground)on it with the 250 ohm load. There is a 4.35 difference between +In and Output.

With no load, Pin 6 has 17.9V and there is 6V between +In and Output.

The voltage difference btween +In and Ouput are the same polarity - one isn't negative.

?

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